The triangle that the height makes would be a 45-45-90 special right triangle. So the height is 3√2, and to find the area, it would be the average of the bases, 7, multiplied by 3√2. So the area of the trapezoid is 21√2.
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Hope this helps!
Set up a proportion to describe this relationship. So, for every 2 cats, there is five dogs. Therefore, “c” can represent your unknown quantity for every 35 animals.
2/5 = c/35
Cross multiply, multiplying the numerator/top number of the first fraction/ratio, by the denominator/bottom number in the second fraction/ratio.
2 • 35 = 70
Then, Cross multiply, multiplying the numerator/top number of the second fraction/ratio, by the denominator/bottom number in the first fraction/ratio.
C • 5 = 5c
So, now the problem shows both products as equal to each other.
70 = 5c
To solve for the variable, “c”, you must isolate the variable, by performing the opposite/inverse operation of multiplication, since that will undo the multiplication, for the variable to stand alone. Therefore, divide both sides of the equation by 5.
70/5 = 5c/5
14 = c
So, there is 14 cats out of 35 animals.
5 times 3 = 15 times 2 = 30 to the power of 2 = 900.
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-procklown