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Setler [38]
2 years ago
8

-10x+10y=-10 10x-10y=10

Mathematics
1 answer:
PSYCHO15rus [73]2 years ago
4 0

Answer:

X=-Y

Step-by-step explanation:

...........................

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10 + 7m = 17
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Subtract 10 and divide by 7
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For two events and , the probability that occurs is 0.8, the probability that occurs is 0.4, and the probability that both occur
sergey [27]

Answer:

P(B|A)=0.25  , P(A|B) =0.5

Step-by-step explanation:

The question provides the following data:

P(A)= 0.8

P(B)= 0.4

P(A∩B) = 0.2

Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.

To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:

P(B|A) = P(A∩B)/P(A)

      = (0.2) / (0.8)  

P(B|A)=0.25

To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:

P(A|B) = P(A∩B)/P(B)

          = (0.2)/(0.4)

P(A|B) =0.5

7 0
3 years ago
The circle for India has a radius of 3.2 cm and the circle for China has a radius of 3.4 cm. If 17% of the world’s population is
defon
World's population that lives in China in percentage is 20%
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Your family needs a set of 4 tires. Which of the following deals would you prefer? Complete the explanation below to tell which
kherson [118]

Answer

Buy 2, get 2 free and/or 1/2 off

Step-by-step explanation:

OK, lets say that the tire price was 15. (l)= 15+15=30 (ll)= 15/45%= 33.33x4=133.32 (lll)= 15/2=7.5   7.5x4=30

6 0
3 years ago
Find the standard form of the equation for the conic section represented by x^2 + 10x + 6y = 47.
Levart [38]

Answer:

The standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Step-by-step explanation:

We know that:

4p\left(y-k\right)=\left(x-h\right)^2 is the standard equation for an up-down facing Parabola with vertex at (h, k), and focal length |p|.

Given the equation

x^2\:+\:10x\:+\:6y\:=\:47

Rewriting the equation in the standard form

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

Thus,

The vertex (h, k) = (-5, 12)

Please also check the attached graph.

Therefore, the standard form of the equation for the conic section represented by x^2\:+\:10x\:+\:6y\:=\:47 is:

4\left(-\frac{3}{2}\right)\left(y-12\right)=\left(x-\left(-5\right)\right)^2

where

vertex (h, k) = (-5, 12)

7 0
2 years ago
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