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Zarrin [17]
3 years ago
11

What is the area of a circle with radius 6 cm? Give your answer in terms of 2 points

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0

22/7*6*6=792/7

792/7=113.142

= 113.14

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What does it mean when a question number is circled in a textbook
RoseWind [281]
This is only my opinion.  I could be wrong.

My guess is:

Somebody else used that book before you, maybe last year or
the year before, and it was somebody who didn't mind writing
in his book.

One day he didn't have time to write down the homework in his
assignment notebook, so he just circled the homework problems
in his textbook.

5 0
3 years ago
The length of a rectangle is 5 cm more than twice the width. The perimeter of the rectangle is 33 cm. Find the dimensions of the
tatiyna
2w+2(5+2w)=33
2w+10+4w=33
6w=22
w=11/3 or 3 and 2/3
7 0
3 years ago
A​ student's course grade is based on one midterm that counts as ​% of his final​ grade, one class project that counts as ​% of
Andrei [34K]

Answer:

The overall score is 75.6

Letter grade is C

Step-by-step explanation:

The question has missing details (See comment section for complete question).

From the complete question, we have:

<u>Proportion:</u>

Midterm = 15\%

Project = 25\%

Assignment = 40\%

Exam = 20\%

Scores

Midterm = 66

Project = 90

Assignment = 75

Exam = 66

Solving (a): The overall score

To do this, we simply calculate the mean of the given data.

The mean is calculated by multiplying each proportion by the scores..

So, we have:

Overall = 15\% * 66 + 25\% * 90 + 40\% * 75 + 20\% * 66

Overall = 9.9 + 22.5 + 30 + 13.2

Overall = 75.6

Solving (b): The letter grade

From the question, we have:

A: Mean \ge 90

B: 80 \le Mean < 90

C: 70 \le Mean < 80

The overall score falls in the following category:

C: 70 \le Mean < 80

Because:

70 \le 75.6 < 80

<em>Hence, the letter grade is C</em>

8 0
2 years ago
Pemfaktoran dari 2x²+5x-18<br><br>​
Harrizon [31]

We can factor a polynomial by finding its roots. In particular, a quadratic equation has (at most) two roots x_1,\ x_2, which would allow us to write the polynomial as

p(x)=a(x-x_1)(x-x_2)

To find the solutions, we can use the quadratic formula

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a} = \dfrac{-5\pm\sqrt{169}}{4} = \dfrac{-5\pm13}{4}

So, the two solutions are

\dfrac{-5+13}{4} = 2\quad\text{and}\quad\dfrac{-5-13}{4} =-\dfrac{9}{2}

And so we can factor the polynomial as follows:

2x^2+5x-18=2(x-2)\left(x+\dfrac{9}{2}\right)

3 0
3 years ago
Find the general solution of the following equation. Express the solution explicitly as a function of the independent variable.
Mashcka [7]

Answer:

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Step-by-step explanation:

Integration Rule:

  1. \int x^n dx= \frac{x^{n+1}}{n+1}+c
  2. \int \frac1x dx= ln(x) +c

Given differential equation is

x^2 \frac{dw}{dx}= \sqrt{w}(2x+5)

\Rightarrow x^2 dw= \sqrt{w} (2x+5) dx    [ multiplying dx both sides]

\Rightarrow \frac{dw}{\sqrt w}= \frac{(2x+5)}{x^2} dx                [ dividing x^2\sqrt w both sides]

Integrating both sides

\int \frac{dw}{\sqrt w}=\int \frac{(2x+5)}{x^2} dx

\Rightarrow \int w^{-\frac12} dw=\int (\frac{2x}{x^2}+\frac{5}{x^2} )dx

\Rightarrow \int w^{-\frac12} dw=\int \frac{2}{x}dx +\int\frac{5}{x^2} dx

\Rightarrow \frac{w^{-\frac12+1}}{-\frac12+1} =2ln x+5 \frac{x^{-2+1}}{-2+1}+c   [ c is arbitrary constant]

\Rightarrow 2 \sqrt w = 2 ln(x) - 5 \frac1x +c

Therefore the general solution is

2 \sqrt w = 2 ln(x) - 5 \frac1x +c

6 0
3 years ago
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