Answer:
Hello! answer: 5
Step-by-step explanation:
What you do to find the answer for these is do a^2+b^2=c^2 Basically meaning 4 × 4 + 3 × 3 will equal a number that you then find the suare root of square root just meaning a number multiplied by itself to equals that number so...
4 × 4 = 16
3 × 3 = 9
16 + 9 = 25
√25 = 5
5 × 5 = 25 therefore c = 5 hope that helps!
Answer:
12x^3 -28x^2 -21x +30
Step-by-step explanation:
1) Distribute!
(6x-5)(2x^2-3x-6) = 12x^3 -18x^2 - 36x -10x^2 +15x+30
2) Combine like terms!
12x^3 -18x^2 - 36x -10x^2 +15x+30 = 12x^3 -28x^2 -21x +30
Answer is:
12x^3 -28x^2 -21x +30
Hope it helps!!
Answer:
^algebra^
#1). a - b=4
a=4 + b .....(equation 1)
#2) a + b=12
(4 + b) + b= 12
4 + b + b=12
4 + 2b=12
2b= 12 - 4
2b =8
b= 8:2
b=4
subtituted b in equation 1
a= 4 + b
a= 4 + 4
a=8
so, the number is 8 and 4
Answer:
6/35 miles per hour
Step-by-step explanation:
To find the unit rate, put distance over time
distance = 1/7 miles
time = 5/6 of an hour
miles/hours
(1/7)/(5/6)
(1/7)*(6/5)
6/35 miles per hour
<span>The graph is attached.
Explanation:We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>