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3 years ago

The points D(9, 8)and E(3, 13) are on a coordinate plane. What is theapproximate distance between points D and E?

Mathematics

1 answer:

Helen [10]3 years ago

5 0

Answer:7.8102 is the distance between those two points

Step-by-step explanation:

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serg [7]

Answer:

Goodluck my dude.

AnswwerrrdexxStep-by-step explanation:

Hi, the answer is goodlick.

5 0

3 years ago

What is the area of these shapes

Llana [10]

Answer. 1: 6x3x3 = 54.

2:6 x 4 = 24 11x 4 =44 44 + 24 =68

Step-by-step explanation: ur welcome

5 0

3 years ago

Which of these points lies on the line discribed by the equation below? y-4= -2(x-6)

Basile [38]

Answer:

C, (6,4)

Step-by-step explanation:

The points (x,y) that lie on the line must fit into the equation correctly. So, we can test out the 4 options to see whether they fit correctly into the equation.

y-4

= -4 -4 = -8

-2(x-6)

= -2 (-6-6)

= 24

Since -8≠24, so A is incorrect.

y -4 = -6-4 = -10

-2(x-6) = -2 (-4-6) = 20

-10≠20, so B is incorrect.

y-4 = 4 -4 = 0

-2(x-6) = -2(6-6) = 0

Both sides are equal. C is correct.

But lets test D out too.

y-4 = 6-4 = 2

-2(x-6) = -2(4-6) = 4

2≠4, so D is incorrect.

6 0

3 years ago

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0). Which type of triangle is ∆ABC? Select All that apply.

stepan [7]

Given:

The coordinates of ∆ABC are A(-3, 2), B(5, 8) & C(11, 0).

To find:

The type of the given triangle.

Solution:

Distance formula:

$D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using the distance formula, we get

$AB=\sqrt{(5-(-3))^2+(8-2)^2}$

$AB=\sqrt{(8)^2+(6)^2}$

$AB=\sqrt{64+36}$

$AB=\sqrt{100}$

$AB=10$

Similarly,

$BC=\sqrt{(11-5)^2+(0-8)^2}$

$BC=\sqrt{(6)^2+(8)^2}$

$BC=\sqrt{36+64}$

$BC=\sqrt{100}$

$BC=10$

And,

$AC=\sqrt{(11-(-3))^2+(0-2)^2}$

$AC=\sqrt{(14)^2+(-2)^2}$

$AC=\sqrt{196+4}$

$AC=\sqrt{200}$

$AC=10\sqrt{2}$

Two sides of the triangle are equal, i.e., $AB=BC$ . So, the triangle is an isosceles triangle.

Sum of square of two smaller side is

$AB^2+BC^2=10^2+10^2$

$AB^2+BC^2=100+100$

$AB^2+BC^2=200$

$AB^2+BC^2=AC^2$

Using the Pythagoras theorem, we can say that the given triangle is a right triangle.

Therefore, the correct options are B and F.

7 0

3 years ago

The quotient of two numbers subtracted from 20

den301095 [7]

Would it be 10-2?=8 quotient means divide

3 0

4 years ago