Let 
be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are
where 
are the positions of trains A and B respectively, and t is the time in hours.
The two trains meet if and only if 
, and we know that this happens after two hours, i.e. at 
Solving this equation for v we have
So, train A is travelling at 105 km/h. This implies that train B travels at
Find the mean, median, and mode of the data set. Round to the nearest tenth. 15, 13, 9, 9, 7, 1, 11, 10, 13, 1, 13 mean = 8.5, m
jasenka [17]
Answer:
Mean = 9.3
Median = 10
Mode = 13
Step-by-step explanation:
To get the mean, you would have to add up all of the numbers (102), then divide how many numbers you have with the numbers added up (9.3). To get the median, you would have to put all of the numbers that you have, in order, from least to greatest and cross off each number, one from each side before getting to the number in the middle (unless if you have an even number; works better with odd numbers, which is easier). To get the mode, you would need to find out which number appears the most, and, if there is more than one, you can put the numbers down. Hope this helps.
Answer:
the bottom one is 1 the second one is 46 and the top one is 500
Step-by-step explanation:
Answer:
7. 21
9. $16,200
Step-by-step explanation:
1. See the attachment for the possible outcomes of rolling two dice. There are 21 ways to get a sum less than 8. (You can count them.)
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2. 1/3 of 1/2 of the total amount of stock is worth $2700. That is 1/6 of the stock, so the worth of all the stock before the sale must be 6 times $2700, or $16,200.
