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dmitriy555 [2]
2 years ago
10

The supplement of a 65° angle has a measure of​

Mathematics
1 answer:
horsena [70]2 years ago
7 0

Answer:

115 degrees

Step-by-step explanation:

supplementary angles add up to 180 degrees, so if x is the angle you're trying to have you get:

x + 65 = 180\\x = 115

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(5+6b^3)^2 expand and combine like terms
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Answer:

( 5 + 6b^3)^2 = 36b^6 + 60b^3 + 25

Step-by-step explanation:

(a + b)^2 = a^2 + b^2 + 2ab

So,

        (5 + 6b^3)^2 = (5)^2 + (6b^3)^2 + 2 (5)(6b^3)

                       = 25 + 36b^6 + 60b^3

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  • 3 times

Step-by-step explanation:

<u>Volume of the pyramid:</u>

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How do I solve for the solution??<br>y = 3x +2<br>y = x + 1​
Elis [28]

Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(−1/2,1/2)

Equation Form:

x=−1/2,y=1/2

Step-by-step explanation:

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3 years ago
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Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
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