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1 year ago

Multiplying Polynomials Distributive Property x^3(x^2+5x-1)

Mathematics

1 answer:

prohojiy [21]1 year ago

8 0

Answer:

x^5+5x^4−x^3

Step-by-step explanation:

Expand by distributing terms

x^3x^2+x^3*5x-x^3

Use the product rule x^a+x^b=x^a+b

x^3+2 +x^3*5x-x^3

Simplify 3+2 to 5

x^5+x^3*5x-x^3

Regroup

x^5+5x^33-3^3

Use product rule x^a+x^b=x^a+b

x^5+5x^3+1 -x^3

Simplify 3+1 to 4

x^5+5x^4−x^3

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some psychologists believe that a genius should be defined as anyone having an IQ over 140. If IQ scores are normally distribute

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Answer:

61,239,550

Step-by-step explanation:

We let the random variable X denote the IQ scores. This would imply that X is normal with a mean of 100 and standard deviation of 17. We proceed to determine the probability that an individual chosen at random from the population would be a genius, that is;

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The next step is to evaluate the z-score associated with the IQ score of 140 by standardizing the random variable X;

$Pr(X>140)=Pr(Z>\frac{140-100}{17})=Pr(Z>2.3529)$

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6,575,000,000*0.009314 = 61,239,550

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2 years ago

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SVETLANKA909090 [29]

Starting January 1, 2015, there are 364 remaining nights.
From 1,001 nights, it will be 637 nights left.

In 2016, there are 366 nights. Subtract it to 637 nights left, you will get 271 nights left.
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3 years ago

What are the missing values in the following geometric sequence?

dezoksy [38]

Answer: 9;0;-3

Step-by-step explanation:

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2 years ago

Is 5 a solution to the equation 2x2 + 10 = 60?

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Answer:

Yes.