Momentum P is conserved because there are no external forces acting on the system.
P before = P after = m₁ v₁ + m₂ v₂
m₁ = 1
m₂ = 5
before:
v₁ = 1
v₂ = 0
Pᵇ = 1·1 + 5 · 0
after:
v₁ = v₂
Pᵃ = Pᵇ
The believe the answer to this is B
We know that P = hρg
Where:
P - pressure Pa,
h - height in meter,
ρ – would be the density in kg / m^3; and
g - acceleration due to gravity is m / s^2
p = hρg if h = 0.735 meter, ρ = 13600 kg / meter^3, g = 10 meter/ sec^2
p = 0.735*13600*10 = 99960 Pa or
P = 1 x 10^5 Pa
Now with sea water if we have to make a barometer:
ρ = 1100 kg / meter^3 (given)
P = hρg if we put the value of P calculated and the value of ρ = 1100 kg /
meter^3 given, we will
get, 1 x 10^5 = h*1100*10
therefore, h = 9.09 meter or 29.82 feet of water.
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The net force is force applied + force friction ( which is negative ) Unfortunately for some reason the numbers are negative, could you ask your teach about that?
Btw, left is usually force fric. which makes it negative
(-750+-250+-550)+1563 = net force
(-792+-632+-100)+(400+900) = net force
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