The work and heat transfer isothermal internally reversible process.
An isothermal procedure is a thermodynamic procedure in which the temperature of a gadget stays consistent. The transfer of heat into or out of the gadget occurs so slowly that thermal equilibrium is maintained. The melting of ice at 0 diploma is an example of isothermal technique. The reaction in a warmth pump is an example of isothermal manner. In Isothermal manner temperature is constant for the duration of the procedure and follows Boyles regulation.
Given,
Gas at initially P1= 2.8 bar
P2 = 14 bar
isothermal reversible process,
Compressed pressure at 60°C
(a) R = 134a
For Refrigerant 134a R134a
At P1 = 14 bar T1 = 600C
S1 = 0.9389 KJ/Kg K
V1 = 264.64 KJ/kg
At
P2 = 2.8 bar T2 = 600C
S2 = 1.1142 KJ/Kg K
V2 = 278.56 KJ/kg
T = 60 + 273 = 333K
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
= 333 ( 1.1142 - 0.9389 )
= 58.3749 KJ/Kg
Heat transfer Q = 58.3749 KJ/Kg
(b) air as an ideal gas.
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
=T-R In P2 P1
= 333 * -0.287 In 2.8 14
= 153.81 KJ/Kg
Heat transfer Q = 153.81 KJ/Kg
W = Q - ΔV
= 28.3749 - (278.56-264.64)
= 14.4549 KJ/Kg
Work W = 14.4549 KJ/Kg
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The magnitude of the acceleration of the runner is given by:

where

is the final speed of the runner

is the initial speed of the runner

is the time taken
By substituting data into the equation, we find the magnitude of the acceleration:
The answer is kinetic energy! Enjoy :)
Answer:
Complete question:
c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?
a.
b.flux through each turn = Ф = 
c.magnitude of the induced emf in the first coil = e= 
Explanation:
a. rate of current changing =
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Induced emf in the coil =e= 
For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law



b.
Flux through each turn=?
Current in the first coil =1.25 A
Number of turns = 20
using MI = NФ
flux through each turn = Ф = 
flux through each turn = Ф = 
c.
second coil increase at a rate = 0.365 A/s
magnitude of the induced emf in the first coil =?
using 

magnitude of the induced emf in the first coil = e= 