<span>the electron configuration of the neutral Atom
1s2 2s1
should be your answer have a good day </span>
3 is the answer your looking for
Answer:
[Kr] 4d² 5s²
Explanation:
In group 2 and period 2 is the element Zirconium. Here's an example A noble gas configuration of an atom consists of the elemental symbol of the last noble gas prior to that atom, followed by the configuration of the remaining electrons. So for sodium, we make the substitution of [Ne] for the 1s22s22p6 part of the configuration. Sodium's noble gas configuration becomes [Ne]3s1.
I believe the correct answer from the choices listed above is the first option. When Br2 and NaF are mixed, no reaction would occur since Br cannot replace F in NaF. By looking at the positions of the halogens in the periodic table, bromine is located way below fluorine. Reactivity of bromine would be low as compared to fluorine so it will not have enough energy to replace fluorine in the compound as it will not have sufficient energy to bind. The position of the halogens are F, Cl, Br, I and At where fluorine is the most reactive element.
Answer:
Maximum number of moles of AlCl3 produced is 5 moles
Explanation:
First thing's first, let's bring out the balanced chemical equation.
2Al + 3Cl2 -> 2AlCl3
Before proceeding to calculating the maximum number of moles of AlCl3 that can be formed, we have to identify the limiting reagent.
Every 2 mole of AlCl3 requires 2 moles of Al and 3 moles of Cl2.
If all of the 5 moles of Al were to be used up, there would need to be 5 × (2 / 3) or 3.333 moles of Cl2. 6 moles of Cl2 is available, this means Al is our limiting reagent.
5 mol of Al * (2 mol of Cl2 / 3 mol of Al) = 3.33 mol of Cl2
From the equation, 2 mol of Al produces 2 mol of AlCl3. This means 5 mol of Al would produce x?
2 = 2
5 = x
x = (5 * 2 ) / 2
x = 10 /2 = 5
Maximum number of moles of AlCl3 produced is 5 moles