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2 years ago

Hallar la altura(h) de un triángulo que tiene una base 12 metros y un área de 96

Mathematics

1 answer:

frez [133]2 years ago

3 0

Answer:

Height of triangle = 16 meter

Step-by-step explanation:

Given:

Area of given triangle = 96 squares meter

Base length of triangle = 12 meter

Find:

Height of triangle

Computation:

Area of triangle = (1/2)(b)(h)

Area of given triangle = (1/2)(Base length of triangle)(Height of triangle)

96 = (1/2)(12)(Height of triangle)

96 = (6)(Height of triangle)

Height of triangle = 96 / 6

Height of triangle = 16 meter

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Find the radius of a circle, when the diameter is 29 cm

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14.5cm

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2 years ago

QUADRATIC FORMULA SIMPLIFIED PLZ HELP

olga2289 [7]

Answer:

3x² + 5x + 1 = 0 simplified

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Step-by-step explanation:

Given quadratic formula

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2 years ago

If the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2:3

horrorfan [7]

Answer: The correct option is (B) 24 : 25.

Step-by-step explanation: Given that the perimeter of square region S and the perimeter of rectangular region R are equal and the sides of R are in the ratio 2 : 3.

We are to find the ratio of the area of R to the area of S.

Let 2x, 3x be the sides of rectangle R and y be the side of square S.

Then, according to the given information, we have

$\textup{Perimeter of rectangle R}=\textup{Perimeter of square S}\\\\\Rightarrow2(2x+3x)=2(y+y)\\\\\Rightarrow 5x=2y\\\\\Rightarrow \dfrac{x}{y}=\dfrac{2}{5}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Therefore, the ratio of the area of R to the area of S is

$\dfrac{2x\times3x}{y\times y}\\\\\\=\dfrac{5x^2}{y^2}\\\\\\=6\left(\dfrac{x}{y}\right)^2\\\\\\=6\times\left(\dfrac{2}{5}\right)^2~~~~~~~~~~~[\textup{Using equation (i)}]\\\\\\=\dfrac{24}{25}\\\\=24:25.$

Thus, the required ratio of the area of R to the area of S is 24 : 25.

Option (B) is CORRECT.

6 0

3 years ago