The expression represents the cost of Janelle’s cell phone bill, where m represents the number of minutes of use.

Fill in the missing information. Tim Worker is doing his budget. He discovers that the average miscellaneous expense is $45.00 w

sleet_krkn [62]

The z for $38.60 = (38.60 - 45)/16 = -0.4

The percent of area associated with $38.60 = P(z < -0.4) = 0.34458 =34.46%

The z for $57.80 = (57.8 - 45)/16 = 0.8.

The percent of area associated with $57.80 = P(z < 0.8) = 0.78814 = 78.81%

the percent of his expenses between $38.60 and $57.80 is (78.81 - 34.46) = 44.35%

4 0

2 years ago

Read 2 more answers

6th grade math plz help me

vlabodo [156]

Answer:

The mode, which is 7, is not a typical distance for the data. The median, which is 3.5, is not a typical distance for the data. The mean, which is 4, is a typical distance for the data. So, Grace’s reasoning is not correct.

5 0

3 years ago

Find the value of x that will make A||B

Arturiano [62]

Answer:

x=20

Step-by-step explanation:

Both Angles have the same value, as they are opposite angels.

Set your formula up as

5x+20=3x+60

5x=3x+60-20

2x=40

x=40/2

x=20

3 0

3 years ago

A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume t

sladkih [1.3K]

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

a)

$\frac{dy}{dt}\ \alpha\ y(1-y)$

$\frac{dy}{dt}=ky(1-y)$

where k is the constant of proportionality, dy/dt = rate at which the rumor spreads

b)

$\frac{dy}{dt}=ky(1-y)\\\frac{dy}{y(1-y)}=kdt\\\int\limits {\frac{dy}{y(1-y)}} \, =\int\limit {kdt}\\\int\limits {\frac{dy}{y}} +\int\limits {\frac{dy}{1-y}} =\int\limit {kdt}\\\\ln(y)-ln(1-y)=kt+c\\ln(\frac{y}{1-y}) =kt+c\\taking \ exponential \ of\ both \ sides\\\frac{y}{1-y} =e^{kt+c}\\\frac{y}{1-y} =e^{kt}e^c\\let\ A=e^c\\\frac{y}{1-y} =Ae^{kt}\\y=(1-y)Ae^{kt}\\y=\frac{Ae^{kt}}{1+Ae^{kt}} \\at \ t=0,y=10\%\\0.1=\frac{Ae^{k*0}}{1+Ae^{k*0}} \\0.1=\frac{A}{1+A} \\A=\frac{1}{9} \\$

$y=\frac{\frac{1}{9} e^{kt}}{1+\frac{1}{9} e^{kt}}\\y=\frac{1}{1+9e^{-kt}}$

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

$y=\frac{1}{1+9e^{-0.8959t}}\\0.75=\frac{1}{1+9e^{-0.8959t}}\\t=3.68\ days$

5 0

2 years ago

Mars has m moons. The number of moons of Pluto is one more than twice the number of moons of Mars. The number of moons of Neptun

tigry1 [53]

Answer:

Neptune has 2 more than 6 times the number of moons on mars

Explanation:

neptune = 6m+2

mars has 'm' moons

pluto has one more than twice that of mars, = 2m+1

neptune is one less than thrice of pluto

= 3(2m+1) -1

= 6m+3 -1

= 6m+2

6 0

2 years ago