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Readme [11.4K]
3 years ago
10

The gas tank if your car is 40%, there are 8 gallons of gas in the tank, what is the capacity of the gas tank?

Mathematics
2 answers:
matrenka [14]3 years ago
8 0
The car holds 20 gallons of gas. 
40%=8
20%=1/2 of 40%
4=1/2 of 8
so 40+40+20=100
8+8+4=20
100%=20 gallons
Tju [1.3M]3 years ago
5 0
40 divided by 8 is 5. Each gallon equals five percent. There are twenty fragments of five percent in 100 percent. The answer is 20 gallons.
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olasank [31]

Answer:

See below:

Step-by-step explanation:

Hello! I hope you are having a nice day.

We can solve this equation in a single step, we just need a bit of theory and a graph.

We can first see that its in y=mx+b form. Which is also known as Slope-Intercept form.

This means that we know the following.

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  • m is the slope of the line.

Since we know that, we can see that from our equation that the slope of the line is 3 and the y intercept is (0,-7).

Now that we've gotten that, we can start graphing.

The y intercept is -7 so we can plot (0,-7) as one of our points.

The slope of 3 means that we got up 3 units then right a single unit.

Therefore, another point could be (1,-4).

With our two points, we can create our graph by creating a straight line through those two points and therefore plotting our line.

Cheers!

6 0
2 years ago
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A certain forest covers an area of 4800km^2. suppose that each year this area decreases by 5% What will the area be after 5 year
mixas84 [53]

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18766224

Step-by-step explanation:

6 0
3 years ago
The length of a rectangular plot is 6m less than thrice its breath. Find the dimensions of the plot if its perimeter is 148m.
Elena-2011 [213]

length of a rectangle is 6 less than 3 times its width"

L = 3W-6

"perimeter of the rectangle is 148 meters"

2L + 2W = 148

L + W = 74

(3W-6) + W = 74

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6 0
3 years ago
Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

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Solving for L:

L = 30 − W

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So the maximum area is:

A = WL

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A = 225

3 0
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Answer:

Step-by-step explanation:

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