<h2>
The first term of the given sequence (a) = 6561</h2>
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and
= 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.

The 3rd term of a G.P.

⇒
= 729 ..............(1)
The 4th term of a G.P.

⇒
= 243 ..............(2)
Dividing equation (2) by (1), we get
=
⇒ 
Put
in equation (1), we get
= 729
⇒
= 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
Answer:
50°
Step-by-step explanation:
Answer: 55
Step-by-step explanation:
D=m/v
D=14.4
M=792
V= unknown
14.4=792/v- multiply both sides by V
V • 14.4=792-divide both sides by 14.4
V=55
I belive [c] is the answer 37/100 47/100
hope this help have a great day :D
The square root of 121 is 11 because 11 times 11 is 121.