Answer: 40
Step-by-step explanation:
ANSWER: 5 minutes 20 seconds
WORK: entire train to get out of tunnel - 2900+300 = 3200 meters till it's out
at 600 meters per minute ...3200/600 = 5 1/3 = 1/3 of a minutes is 20 seconds
Hope this helps brainliest and rate/thanks helps!
Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
a) ∠PQR=65° (alternate interior angles theorem)
∠PRQ = 60° (linear pair)
x = 55° (angles in a triangle add to 180°)
b) ∠APQ and ∠PQR are congruent alternate interior angles.
