Answer:
C(p) = p*50 + 300
Step-by-step explanation:
Using the names:
Clm: cost of labor and materials
Crm: fixed cost on rent and equipment
p: number of phones
and Ct: total cost
the ecuation would be number of phones times the cost and material plus the fixed cost, something like this
p * Clm + Crm = Ct
on the example we have all the data except the rent and equipment cost (the fixed cost) so thats what we need to solve
producing 3 phones its
3 *¨50 + Crm = 450
Crm = 450 - 150 = 300
so replacing in the above formula the equation would be
C(p)=p * 50 + 300
Answer:
-27.26 ----------- -52.89 - (-25.63)
135.03 ----------- 49.40 - (-85.63)
-120(2)/(3) ----------- -96(2)/(9) - 24(4)/(9)
-15(3)/(5) ----------- -18(1)/(5) - [-2(3)/(5)]
Answer:
12.5
Step-by-step explanation:
.25 x 50= 12.5
Answer:
The zeros of f(x) are: (x - 1), (x - 3) and (x - 8)
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Step-by-step explanation:
Given
Required
Find all zeros of the f(x)
If then:
And 
is a factor
Divide f(x) by x - 8
Expand the numerator
Rewrite as:
Factorize
Expand
Factorize
Multiply both sides by x - 8
<em>Hence, the zeros of f(x) are: (x - 1), (x - 3) and (x - 8)</em>
Answer:
$<em>150,858.5</em>
Step-by-step explanation:
The formula for calculating compound interest is expressed as;
A = P(1+r/n)^nt
P is the Principal = $124000.00
r is the rate = 12% = 0.12
t is the total time = 2 years
n is the time of compounding = 1/4 = 0.25(quarterly)
Substitute into the formula;
A= 124000(1+0.12/(0.25))^(0.25)(2)
A = 124000(1+0.48)^0.5
A = 124000(1.48)^0.5
A = 124000(1.2166)
A = 150,858.5
<em>The amount after 2 years if compounded quarterly is 150,858.5</em>
