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3 years ago

Identify the zeros of the following function. f(h)=h(h-2)(2h-1)

1 answer:

5 0

{0, 2, 1/2}

f(h) = 0 when any set of parenthesis equals zero

1. h = 0

2. h - 2 = 0
add 2
h = 2

3. 2h - 1 = 0
Add 1
2h = 1
divide by 2
h = 1/2

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Initially, the ratio of Ed’s toy cars to Pete’s toy cars was 5:2. After Ed gave 30 toy cars to Pete, they each had an equal numb

Burka [1]

So here is the answer. Initially, Ed's toy cars compared to Pete's toy cars was 5:2. So for every 5 cars that Ed has, Pete has 2. Now that Ed gave 30 cars to Pete. So here it goes. The total number of ratio units is 5+2=7, so each will have an equal number if they both have 3.5 ratio units. That is, if Ed transfers to Pete 1.5 ratio units, their car counts will be equal. Thus 1.5 ratio units = 30 cars, or 1 ratio unit = 20 cars. Therefore, this makes <span> 7*20 cars = 140 cars.
</span>Hope this helps.

6 0

2 years ago

HELP PLEASE.................

Kryger [21]

Zero

There is no solution for these equations as there is no even one point of intersection between them

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2 years ago

Help appreciated on question in image!<br> Thanks:)

Verdich [7]

Answer:

$x=-1,\:x=-7,\:x=i,\:x=-i$

Step-by-step explanation:

Considering the equation

$x^4+8x^3+8x^2+8x+7=0$

Solving

$x^4+8x^3+8x^2+8x+7$

$\mathrm{Factor\:}x^4+8x^3+8x^2+8x+7:\quad \left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

$\mathrm{Use\:the\:rational\:root\:theorem}$

$a_0=7,\:\quad a_n=1$

$\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:7,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1$

$\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:7}{1}$

$-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1$

$=\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

Solving

$\frac{x^4+8x^3+8x^2+8x+7}{x+1}$

$=x^3+7x^2+x+7$

Putting $\frac{x^4+8x^3+8x^2+8x+7}{x+1}$ = $x^3+7x^2+x+7$ in equation [A]

So,

$\left(x+1\right)\frac{x^4+8x^3+8x^2+8x+7}{x+1}...[A]$

$=\left(x+1\right)x^3+7x^2+x+7$

$x^3+7x^2+x+7=\left(x+7\right)\left(x^2+1\right)$

So,

Equation [A] becomes

$=\left(x+1\right)\left(x+7\right)\left(x^2+1\right)$

So, the polynomial equation becomes

$\left(x+1\right)\left(x+7\right)\left(x^2+1\right)=0$

$\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$ $\mathrm{Solve\:}\:x+1=0:\quad x=-1$

$\mathrm{Solve\:}\:x+7=0:\quad x=-7$

$\mathrm{Solve\:}\:x^2+1=0:\quad x=i,\:x=-i$

$\mathrm{The\:solutions\:are}$

$x=-1,\:x=-7,\:x=i,\:x=-i$

Keywords: polynomial equation

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5 0

2 years ago

Read 2 more answers

Explain how the pythagorean theorem is used to derive the distance formula

kenny6666 [7]

Answer:

In the Pythagorean Theorem, a right triangles hypotenuse is found by a^2 +b^2= c^2. The distance formula is basically the same thing. With two points, a right triangle can be formed and the slop would be the hypotenuse. That's where the distance formula comes from

Step-by-step explanation:

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3 years ago

Please answer for me appreciate it

miss Akunina [59]

Finding slope?
5. Slope is 5/3
6. Slope is 7/3
7. Slope is -3
8. Slope is 7/3

Just do rise/run

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2 years ago