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Pavlova-9 [17]
3 years ago
12

Will give branliest!

Chemistry
1 answer:
Fiesta28 [93]3 years ago
4 0

Answer:

0.058 g of Al₂O₃

Explanation:

Al₂O₃ → Aluminum oxide

The molar mass is 101.96 g/mol. Therefore 1 mol (NA molecules) are contained in 101.96 grams

NA = Avogadro's number → 6.02×10²³

We make a rule of three to determine the grams we were asked for.

6.02×10²³ molecules are contained in 101.96 g

3.45×10²⁰ molecules will be contained in (3.45×10²⁰ . 101.96 g ) / NA = 0.058 g

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