The compound formed is the quaternary ammonium salt N,N,N-trimethyl-1-phenylmethanaminium iodide.
Quaternary ammonium salts are formed when methyl iodide reacts with an amine. The quaternary ammonium salt is an ionic substance which often has a high melting point. Remember that the melting point of a substance can be used to identify the substance.
In this case, a student reacted 40 drops of an unknown amine with 20 drops of iodomethane in 2 ml of a suitable solvent mixture. after 15 minutes of reaction, a white precipitate formed. the precipitate was isolated and its melting point was recorded to be 178 °c. This precipitate must be N,N,N-trimethyl-1-phenylmethanaminium iodide (Benzyltrimethylammonium iodide) because it is a quaternary ammonium salt whose melting point is 178 °c.
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Answer:
Option C.
The Bohr effect describes the effect of pH on the affinity of hemoglobin for oxygen.
Explanation:
The hemoglobin is the oxygen carrying part of the blood. However, According to Christian Bohr, the binding affinity for oxygen by the hemoglobin in the blood is greatly affected by the acidity and content of carbon dioxide in the blood. As a matter of fact, they are inversely related. The more acidic the blood is, or the lower the pH of the blood, the lower the amount of oxygen that can become bonded with the hemoglobin in the blood.
Scientists use carbon-14 to date ancient fossils.
Plants and animals absorb carbon-14 produced by cosmic rays. The ratio of C-14 to C-12 is constant when they are alive.
When they die, the C-14 decays to C-12, and the ratio changes.
Carbon-14 has a half-life of 5730 years. Thus, the object loses half its C-14 every 5730 years.
Scientists can use the C-14 to C-12 ratio to date fossils up to 70 000 years old.
Earnest Rutherford was JJ Thomson’s student. He disproved Thomson’s plum pudding model. So Rutherford comes after Thomson. Dalton is first because you should be aware of Daltons atomic theory on the atom. He was one of the first people to actually make a theory about atoms in that type of detail. Bohr came last. I forgot what Bohr’s model was, but you can do a quick google search if you want.
So your answer is B, the second one
Answer:
Here's what I get
Explanation:
There are two methods of naming esters.
(a) Common names
alkyl alcohol + carboxylic acid ⟶ alkyl carboxylate
To form the name of an ester, you drop the alcohol and -ic acid ending from the names of the reactants.
The name of the ester consists of two words: the name of the alcohol followed by the acid name with the ending -ate.
(b) IUPAC (systematic) names
alkanol + alkanoic acid ⟶ alkyl alkanoate
To form the name of an ester, you drop the -anol and -ic acid endings from the names of the reactants.
The name of the ester consists of two words with the corresponding endings -yl and -ate.
You don't mix the common and IUPAC systems in the same name.
1. ethanol + benzoic acid ⟶ ethyl benzoate
2. benzyl alcohol + acetic acid ⟶ benzyl acetate
3. butanol + butanoic acid ⟶ butyl butanoate (IUPAC)
butyl alcohol + butyric acid ⟶ butyl butyrate (common)
4. pentanol + propanoic acid ⟶ pentyl propanoate (IUPAC)
n-pentyl alcohol + propionic acid ⟶ n-pentyl propionate (common)
5. isopropyl alcohol + formic acid ⟶ isopropyl formate
