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3 years ago

Every summer I drive to San Diego. It is 700 km to get there. If I average 100 km/hr, how much time will I spend driving?

Mathematics

1 answer:

Ilya [14]3 years ago

4 0

Answer: 7 hours

Step-by-step explanation: Driving one kilometer per hour, all you have to do is divide 700/100 to get your answer which is seven.

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The ratio of 6 hours and 48 minutes in simplest form is (I need this quickly)

julsineya [31]

The gcf of both 6 and 48 is 6. So, in simplest form, the ration would be: 1:6 or 1 hour:6 minutes :)

7 0

2 years ago

Find the area of the figure 40 yd 36 yd 20 yd 10 yd 10 yd

Ksenya-84 [330]

Answer:

1640yd

Step-by-step explanation:

10*10*2=200

36*40=1440

200+1440=1640 yd

4 0

3 years ago

What is the equation of a line thats passes through point (10, 5) and is perpendicular to the line whose equation is y=5/4x-2

Sauron [17]

Answer: y = -4x/5 + 13

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c represents the y intercept

m represents the slope of the line.

The equation of the given line is

y = 5x/4 - 2

Comparing with the slope intercept form, slope = 5/4

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line passing through (10, 5) is - 4/5

To determine the y intercept, we would substitute m = - 4/5, x = 10 and y = 5 into y = mx + c. It becomes

5 = - 4/5 × 10 + c

5 = - 8 + c

c = 5 + 8 = 13

The equation becomes

y = -4x/5 + 13

4 0

3 years ago

Let A = 2, B = 3, C = 9, and D = 15.

bogdanovich [222]

Step-by-step explanation:

Put A = 2, B = 3, C = 9 and D = 15 to the given expressions.

Use PEMDAS.

-A + C - (D : B)

-2 + 9 - (15 : 3) = -2 + 9 - 5 = 7 - 5 = 2

B × (-C) - (-D) + A

3 × (-9) - (-15) + 2 = -27 + 15 + 2 = -12 + 2 = -10

(C + D) : B + A

(9 + 15) : 3 + 2 = 24 : 3 + 2 = 8 + 2 = 10

D : B + A - C

15 : 3 + 2 - 9 = 5 + 2 - 9 = 7 - 9 = -2

7 0

3 years ago

P varies directly as the cube root of Q. If P = 4 when Q = 8, find P when Q = 64

NemiM [27]

Step-by-step explanation:

P varies directly as the cubic root of Q means that:

$p = x \times \sqrt[3]{q}$

, where x is a real constant number.

Which means that:

$x = \frac{p}{ \sqrt[3]{q} }$

for q ≠0.

So we get that for q=8,p=4 which means:

$x = \frac{4}{ \sqrt[3]{8} } = \frac{4}{2} = 2$

As a result we get that for Q=64:

$p = 2 \times \sqrt[3]{64} = 2 \times 4 = 8 \\ since \: {4}^{3} = 4 \times 4 \times 4 = \\ 16 \times 4 = 64$

So for q=64,p=8.

8 0

3 years ago

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