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Andru [333]
3 years ago
13

A basketball coach is purchasing 12 shirts for her team, each with a different number. At the checkout counter, the clerk places

5 of the shirts in the first bag. How many different ways can a group of 5 shirts be placed in that first bag? A. 19,008
B. 60
C. 792
D. 95,040
Mathematics
2 answers:
ICE Princess25 [194]3 years ago
4 0
Kidjov the answer I came up with for you is 792 I hope this helps
kaheart [24]3 years ago
4 0

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

Total number of shirts purchased for her team = 12

Number of shirts places in the first bag = 5

We need to find the number of ways a group of 5 shirts be placed in that first bag.

We will use "Combination" to find the number of different ways :

As we know the formula for Combination.

^nC_r=\frac{n!}{r!\times (n-r)!}\\\\here, n=12\\\\r=5\\\\So,\ it\ becomes,\\\\^{12}C_5=\frac{12!}{5!\times 7!}\\\\=\frac{12\times 11\times 10\times 9\times 8}{5\times 4\times 3\times 2}\\\\=792

Hence, there are 792 ways to do so.

Therefore, Option 'C' is correct.


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Answer : There are no more than 10% of homes in the city are not up to the current electric codes but actually we do not have evidence to accept it.

Explanation:

The Type I error occurs when the null hypothesis is true but we reject it.

Given null hypothesis : H_0 : an electrician claims that no more than 10% of homes in the city are not up to the current electric codes.

The Type I error for the given situation is that there are no more than 10% of homes in the city are not up to the current electric codes but actually we do not have evidence to accept it.

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What is the value of (10 x 0.5) squared + 4 cubed?
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2 years ago
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Q1.  Look at the picture.

C.\\y=-\dfrac{1}{3}x+3\\\\y=2x-4

Q2. Look at the picture.

A.\ 4-t

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\left\{\begin{array}{ccc}n=3m-11&(*)\\2m+3n=0&(**)\end{array}\right

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