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Alenkinab [10]
3 years ago
6

Pythamgorean theorem

Mathematics
1 answer:
Vesna [10]3 years ago
8 0

Answer:

What about Pythagorean Theorem?

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PLEASE HELP!! DUE SOON
zhenek [66]

Answer:

C is false as the other three are 100% correct statements. I dont know what is linear growth and exponential growth but I know that the other 3 statements are correct so the only 1 left C must be false.

4 0
3 years ago
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Translate the phrase into a math expression. 30 added to a number that is decreased by 5
grin007 [14]
If you want to translate the phrase 30 added to a number that is decreased by 5 into a math expression, you can do it like this:

a number ... n
30 added ... + 30
decreased by 5 ... - 5

Now you just have to put this together: n + 30 - 5 or n - 5 + 30. So, the correct result is a.

3 0
3 years ago
Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir
kati45 [8]
\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad 
radius=\stackrel{}{ r}\\\\
-------------------------------\\\\
(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~
\begin{cases}
\stackrel{center}{(-1,0)}\\
\stackrel{radius}{6}
\end{cases}

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad 
%  distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}
\\\\\\
d=\sqrt{0+1}\implies d=1

well, the distance from the center to A is 1, namely is "inside the circle".

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\
\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}
\\\\\\
d=\sqrt{0+36}\implies d=6

notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad 
C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})
\\\\\\
\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}
\\\\\\
d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
3 0
3 years ago
Read 2 more answers
2. Simplify 2x + 16 + 5x – 10​
Sliva [168]

Answer: 7x + 6

Step-by-step explanation:

Combine like terms:

(2x + 5x) + (16 - 10)

5 0
3 years ago
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What is the length of the base of a right triangle with an area of 24 m² and a height of 4 m?
max2010maxim [7]
Area of triangle = 1/2 × base × height
so,
24=1/2*base*4
base=12m
7 0
4 years ago
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