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BlackZzzverrR [31]
3 years ago
14

A football player attempts to kick a football over a goal post. The path of the football can be modeled by the function ,

Mathematics
2 answers:
lukranit [14]3 years ago
4 0
The parent exponential function:

y=ab^x
STALIN [3.7K]3 years ago
3 0

Answer:

y=ab^x  

Step-by-step explanation:

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HELP 100 POINTS The population of a city is modeled with the function P=250,000e^0.013t​, where t is the number of years since 2
erma4kov [3.2K]
Pretty difficult problem, but that’s why I’m here.
First we need to identify what we’re looking for, which is t. So now plug 450k into equation and solve for t.
450000 = 250000e^0.013t
Now to solve this, we need to remember this rule: if you take natural log of e you can remove x from exponent. And natural log of e is 1.
Basically ln(e^x) = xln(e) = 1*x
So knowing this first we need to isolate e
450000/250000 = e^0.013t
1.8 = e^0.013t
Now take natural log of both
Ln(1.8) = ln(e^0.013t)
Ln(1.8) = 0.013t*ln(e)
Ln(1.8) = 0.013t * 1
Now solve for t
Ln(1.8)/0.013 = t
T= 45.21435 years
Now just to check our work plug that into original equation which we get:
449999.94 which is basically 500k (just with an error caused by lack of decimals)
So our final solution will be in the 45th year after about 2 and a half months it will reach 450k people.
6 0
2 years ago
Name the parts of the expression then, write it in expanded form. a. 14b b.30jk
Makovka662 [10]

Answer:

a. 14 is a coefficient, and b is a variable.

This can be expanded to 14*b

b. 30 is a coefficient, and j and k are variables.

This can be expanded to 30*j*k

3 0
2 years ago
If an investment of $3000 grows to $4432.37 in eight years with interest compounded annually , what is the interest rate?
melamori03 [73]
\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\to &\$4432.37\\
P=\textit{original amount deposited}\to &\$3000\\
r=rate\to r\%\to \frac{r}{100}\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &8
\end{cases}

\bf 4432.37=3000\left(1+\frac{r}{1}\right)^{1\cdot 8}\implies \cfrac{4432.37}{3000}=(1+r)^8
\\\\\\
\sqrt[8]{\cfrac{4432.37}{3000}}=1+r\implies \sqrt[8]{\cfrac{4432.37}{3000}}-1=r
\\\\\\
0.0500001086\approx r\qquad\qquad\cfrac{r\%}{100}\approx 0.0500001086
\\\\\\
r\%\approx 100\cdot 0.0500001086\implies r=\stackrel{\%}{5}
6 0
3 years ago
HELP pleaseeeeeeeeeeeeeeeee
Yanka [14]
2 rows of geraniums and 4rows of the other one
3 0
2 years ago
Read 2 more answers
Molly earns a rebate each month on her movie tickets and books. She earns $0.25 for each movie ticket and $2 for each book. Last
Sliva [168]

The algebraic equation is 4(0.25)+2x=17

STEP 1: Simplify both sides of the equation

1+2x=17  or  2x+1

STEP 2: Subtract both sides

2x = 16

STEP 3: Divide both sides by 2

2x/2 = 16/2

x = 8

Molly purchased 8 books last month

7 0
3 years ago
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