All categories

3 years ago

Which graph shows exponential growth?

Mathematics

2 answers:

adelina 88 [10]3 years ago

8 0

Answer:

the secoond one

Step-by-step explanation:

GarryVolchara [31]3 years ago

4 0

Answer:

The second graph.

Step-by-step explanation:

It keeps getting steeper. This means that it is growing exponentially.

You might be interested in

What's the solution to the inequality ??

stealth61 [152]

X<-2

hope this helped!

4 0

3 years ago

Read 2 more answers

The sum of 4 consecutive integers is 406. find the integers

BabaBlast [244]

Answer and Step-by-step explanation:

When trying to figure this out, we know that the numbers have to be one after the other, like 1, 2, 3, 4, or 55. 56, 57, 58. The last digit in the numbers also have to add to 6.

The answer is:

100 + 101 + 102 + 103

It adds up to 406, and the integers are consecutive.

#teamtrees #PAW (Plant And Water)

I hope this helps!

8 0

2 years ago

Read 2 more answers

Use the figure below. What is m

tankabanditka [31]

Answer:

150

Step-by-step explanation:

90-60 is 30

180-30 is150

3 0

2 years ago

Can I get help with finding the Fourier cosine series of F(x) = x - x^2

trapecia [35]

Assuming you want the cosine series expansion over an arbitrary symmetric interval $[-L,L]$ , $L\neq0$ , the cosine series is given by

$f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx$

You have

$a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx$
$a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}$
$a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)$
$a_0=-\dfrac{2L^2}3$

$a_n=\displaystyle\frac1L\int_{-L}^Lf(x)\cos nx\,\mathrm dx$

Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

$\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}$

and so

$a_n=-\dfrac{4L\cos nL}{n^2}+\dfrac{(4-2n^2L^2)\sin nL}{n^3}$

So the cosine series for $f(x)$ periodic over an interval $[-L,L]$ is

$f_C(x)=-\dfrac{L^2}3+\displaystyle\sum_{n\ge1}\left(-\dfrac{4L\cos nL}{n^2L}+\dfrac{(4-2n^2L^2)\sin nL}{n^3L}\right)\cos nx$

4 0

3 years ago

How do you solve this?

Effectus [21]

Answer:

shheeeesh that is hard good luck

6 0

2 years ago