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creativ13 [48]
2 years ago
5

EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

EEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE EEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE
Mathematics
2 answers:
mestny [16]2 years ago
5 0

Answer:

This man is valid

Bess [88]2 years ago
3 0

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

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Alex earn 12% Commission on any of her monthly sales over $5,000 for sales for May were $6,750 how much commission did Alex earn
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–12.3 – 14.2 <br><br> A. 0.9 <br> B. 26.5 <br> C. –0.9 <br> D. –26.5
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Answer:

-26.5

Step-by-step explanation:

-12.3 - 14.2 =

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3 years ago
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Paraphin [41]

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Where’s the graph?

Step-by-step explanation:

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2 years ago
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You calculated probabilities involving various blood types. Some of your answers depended on the assumption that the outcomes de
Natali5045456 [20]

Answer:

a) The events are disjoint, because a person cannot have blood type A and blood type B at the same time.

b) The events are independent, because the probability of having blood type does not depend on other persod having blood type B.

c) Yes, disjoint events are independent if and only if the probability of some of the events is zero.

Step-by-step explanation:

a) Let the events be:

A: "the person has blood type A

B: the person has blood type B

As a person can only have one blood type these events are disjoint.

b) If we examine two people, let the events be that the first is blood Type A and the second blood Type B:

The events are independent because the probability of the first person having blood type A does not influence the probability of the second person having blood type B (unless the two people are related).

c) Two events are independent if and only if:

P(A∩B)=P(A)×P(B)

Given the events A and B which are disjoint:

P(A∩B)=0

Hence, A and B could be independent events if and only if the probability of one of the events is 0.

3 0
2 years ago
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