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Pani-rosa [81]
3 years ago
10

Amy is making a cookie recipe which uses 1/2 teaspoon of sugar per batch. She wants to make 5 batches. How many teaspoons of sug

ar will she use?
Mathematics
2 answers:
Serggg [28]3 years ago
8 0
The answer is 2 and a half 2 1/2
faust18 [17]3 years ago
3 0
If 1 patch = 1/2 teaspoon
then 5 patches = x             (cross multiply)
1 × x = 5 × 1/2
x = 5/2
x = 2  1/2
therefore 5 patches would use two and a half teaspoons
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The speed that a tsunami can travel is modeled by the equation s = 356 startroot d endroot , where s is the speed in kilometers
Naddika [18.5K]

The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

<h3>What is speed?</h3>

Speed can be calculated as the ratio of distance traveled to the time taken.

The speed that a tsunami can travel is modeled by the equation

s = 356√d, where s is the speed in kilometers per hour and d is the average depth of the water in kilometers.

S = 356√d

200 = 356√d

√d = 200/356

= 0.5618

d = 0.5618^2

= 0.316 km

d = 0.32 km.

Thus, The approximate depth of water for a tsunami traveling at 200 kilometers per hour is 0.32 km.

Learn more about speed;

brainly.com/question/4723349

8 0
2 years ago
How do you solve this?
puteri [66]

Answer:

Width: 7

Length: 14

Step-by-step explanation:

The area of a rectangle can be found my multiplying the length by the width. We do not know neither the length nor the width. However, we do know that the length is 7 feet longer than the width. Because we do not know the value of either side, let's let x represent the width.

Since the length is 7 feet longer, we can represent the length by x+7.

Now that we have our values for the length and the width we can multiply them together to find our area.

(x)(x+7)=x^{2} +7x

Now we have our equation, so we can address the changes made by the original question. The original question states that when 7 is added to both the length and width the area becomes 3 times larger. To do so simply increase each side by 7 by adding 7 to the original values.

(x+7)(x+14)

And multiply our area by 3.

3(x^{2} +7x)

set these equal to each other to find your new equation.

(x+7)(x+14)=3(x^{2} +7x)

Now you need to solve for x. To do this first muliply (x+7) and (x+14).

(x+7)(x+14)=\\x^{2} +14x+7x+98=\\x^{2} +21x+98

Then multiply 3(x^{2} +7x)

3(x^{2} +7x)=\\3x^{2} +21x

Now you can begin solving for x.

x^{2} +21x+98=3x^{2} +21x

Subtract x^{2} from both sides.

21x+98=2x^{2} +21x

Subtract 21x from both sides.

98=2x^{2}

Divide by 2.

49=x^{2}

And finally take the sqaure root of both sides.

\sqrt{x^{2} }=\sqrt{49}\\x=7

Remember, because we are dealing with length, there cannot be negative. So while normally we would get both +7 <em>and</em> -7, in this case we <em>only </em>get +7.

Now that we have the value of x, we can plug it into our original values.

For width we simply get 7.

For length we get 7+7=14

To check our answer we cna multiply 7 by 14 to get 98. Then we can add 7 to our length and width to get 14 and 21. Multiply these together and we get 294. 294 divided by 3 is 98, proving our answer correct.

7 0
3 years ago
Find the sum of ∠BCD and ∠SBT in terms of x.
AleksAgata [21]
Let's\ \angle TCB=y^o\\\\\angle SBT\ is\ the\ exterior\ angle\ of\ \Delta TCB,\ therefore\ |\angle SBT|=x^o+y^o.\\\\|\angle\ BCD|\ +\ y^o=180^o-angles\ on\ one\ side\ of\ a\ straight\ line\\\\|\angle BCD|=180^o-y^o\\\\therefor\\\\\angle SBT+\angle BCD=x^o+y^o+180^o-y^o=x^o+180^o\\\\\boxed{Answer:\angle SBT+\angle BCD=x^o+180^o}
4 0
3 years ago
Read 2 more answers
A factory-made 100,000 jars of peanut butter. 50,000 of the jars contained creamy peanut butter. What percentage of the jars of
snow_tiger [21]

Answer:

50%

hope this answer helps you!

3 0
3 years ago
1. Divide 6x^4 + 2x^3 – 6x^2 – 14x – 1 by 3x + 1 by using synthetic division or long division. Show all
iris [78.8K]
                  2x^3 - 2x - 4

3x + 1        6x^4 + 2x^3 - 6x^2 - 14x - 1
                  6x^4 + 2x^3
                
                                       -6x^2 - 14x - 1
                                       -6x^2 - 2x
     
                                                 -12x - 1
                                                 -12x - 4
 
                                                           3

3x + 1 is not a factor of the dividend because, dividing the dividend with 3x + 1 gives a remainder.
5 0
3 years ago
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