64.96 litre of oxygen is produced at STP when 3.56 x 10^24 molecules of water is decomposed into hydrogen gas and oxygen gas.
Explanation:
The balance equation for the decomposition of water in to hydrogen gas and oxygen gas is:
2H20-------------------------- 2H2+ 02
the oxygen formed from the decomposition reaction is 0.5 moles
So, number of molecules of oxygen are
0.5*3.56*10^24
= 1.78 *10^23 moles of oxygen gas produced.
We know that 1 mole contains
6.023*10^23 particles
So total amount produced is:
1.78*10^24/6.02*10^23
2.9 moles
we know that at STP, the temperature is 273K, Pressure is 1 atm, volume is 22.4 litres
So the volume of oxygen produced will be given by:
22.4*2.9
=64.96 Litres
