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Art [367]
3 years ago
15

How many grams of Fe2O3 will be produced from 37.5 grams of iron

Chemistry
1 answer:
Harman [31]3 years ago
3 0

Step 1 : Convert mass of Iron to moles using n = m/MM.

n(Fe) = 37.5 ÷ 55.845 = 0.671501... mol

Step 2 : Using stoichiometric ratios, find how many moles of Fe2O3 are produced.

Fe : Fe2O3 is 4:2, or simply 2:1. For every 2 moles of Fe there is Fe2O3.

Therefore, moles of Fe2O3 is half the amount of Fe!

n(Fe2O3) = 0.5 x 0.671501... = 0.33575... mol

Step 3: Convert the moles of Fe2CO3 to mass using m = n x MM.

m(Fe2O3) = 0.33575... x [2(55.845)+3(15.999)] = 53.61502... grams

Final step: round your answer to the lowest signficant figures. Since you gave me the mass of iron to 3s.f, m(Fe2O3) = <u><em>53.6 grams</em></u> (3s.f) !

Let me know if you're confused in any way!

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How many molecules are in 145.5 grams of Be(OH)2
Zanzabum

Answer:

2.04 x 10²⁴ molecules

Explanation:

Given parameters:

Mass of Be(OH)₂ = 145.5g

To calculate the number of molecules in this mass of Be(OH)₂ we follow the following steps:

>> Calculate the number of moles first using the formula below:

Number of moles = mass/molarmass

Since we have been given the mass, let us derive the molar mass of Be(OH)₂

Atomic mass of Be = 9g

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H = 1g

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Number of moles = 145.5/43 = 3.38mol

>>> We know that a mole is the amount of substance that contains Avogadro’s number of particles. The particles can be atoms, molecules, particles etc. Therefore we use the expression below to determine the number of molecules in 3.38mol of Be(OH)₂:

Number of

molecules= number of moles x 6.02 x 10²³

Number of molecules= 3.38 x 6.02 x 10²³

= 20.37 x 10²³ molecules

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