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3 years ago

2x 2 - 4x + 6 = 0 is in general form.

Mathematics

1 answer:

d1i1m1o1n [39]3 years ago

8 0

2x² - 4x + 6 = 0 /:2

x²-2x+3=0

Δ=(-2)²-4·1·3=4-12=-8<0

x∈∅

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hichkok12 [17]

Answer:

The coordinates of C(22/3, 7)

Step-by-step explanation:

Partitioning between two points A and B in the ratio a:b.

The x-coordinate of the point of partition C is found at

XC = XA*(b/(a+b)+XB(a/(a+b) ..............(1)

Similarly, the x-coordinate of the point of partition is found at

YC = YA*(b/(a+b)+YB(a/(a+b)...............(2)

Given A(8,8), B(4,2), partition ratio of A:B = 1:5,

substitute in (1)

XC = 8*5/6+4*1/6 = 44/6 = 22/3

YC = 8*5/6 + 2*1/6 = 42/6 = 7

The coordinates of C(22/3, 7)

7 0

3 years ago

4 2/7 ÷3 4/5=<br> how do you answer this?

Pavel [41]

is it 42 or 4 and 2 separate

6 0

3 years ago

Use the order of operations to solve. Please write the problem number on your paper and show your work for this problem. Work wi

umka21 [38]

To this question, 533 is the answer

5 0

4 years ago

Read 2 more answers

Find the area of the shaded region.

lbvjy [14]

Answer:

$48\pi\\\approx 150.796$

Step-by-step explanation:

1.Approach

To solve this problem, find the area of the larger circle, and the area of the smaller circle. Then subtract the area of the smaller circle from the larger circle to find the area of the shaded region.

2.Find the area of the larger circle

The formula to find the area of a circle is the following,

$A=(\pi)(r^2)$

Where (r) is the radius, the distance from the center of the circle to the circumference, the outer edge of the circle. ( $\pi$ ) represents the numerical constant (3.1415...). One is given that the radius of (8), substitute this into the formula and solve for the area,

$A_l=(\pi)(r^2)\\A_l=(\pi)(8^2)\\A_l=(\pi)(64)$

3.Find the area of the smaller circle

To find the area of the smaller circle, one must use a very similar technique. One is given the diameter, the distance from one end to the opposite end of a circle. Divide this by two to find the radius of the circle.

8 ÷2 = 4

Radius = 4

Substitute into the formula,

$A_s=(\pi)(r^2)\\A_s=(\pi)(4^2)\\A_s=(\pi)(16)$

4.Find the area of the shaded region

Subtract the area of the smaller circle from the area of the larger circle.

$A_l-A_s\\=64\pi - 16\pi\\=48\pi$

$\approx150.796$

5 0

3 years ago

Solve (x to the fourth power - 6) ×7+3=

abruzzese [7]

First multiply everything inside the brackets by seven
7x^4-42+3
Then solve what you can
7x^4-39
You an't solve it further. Is this what you mean? X to the fourth power?

6 0

4 years ago