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natka813 [3]
3 years ago
8

4. Find 2 solutions to 2x>-20

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
3 0
Answers: There are an infinite number of solutions. Any two values larger than -10 will work.

To find the list of solutions, we have to solve the inequality.

2x > -20  Divide both sides by 2

x > -10

Therefore, any numbers greater than -10 are solutions.
You might be interested in
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
3 years ago
7/8m+9/10-2m-3/5<br> Combine like terms to create an equivalent expression.
stich3 [128]

Answer:

-1.123m+0.3

or in fraction form -9/8m+3/10

Step-by-step explanation:

first you subtract 7/8 from 2

then you subtract again 9/10 from 3/5

4 0
3 years ago
PLEASE HELP
lbvjy [14]

any other details you could give me ?

8 0
3 years ago
H e l p p l e a s e ; - ;
irina1246 [14]

Answer:

9/4

Step-by-step explanation:

if you use cross multiplication you can see that it would cross eachother out and becom one plz vote brainliest

5 0
3 years ago
-3(-4r - 5)<br> combining like terms
svp [43]

Answer:

r

=

1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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