Answer:
(−0.103371 ; 0.063371) ;
No ;
( -0.0463642, 0.0063642)
Step-by-step explanation:
Shift 1:
Sample size, n1 = 30
Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm
Shift 2:
Sample size, n2 = 25
Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17
Mean difference ; μ1 - μ2
Zcritical at 95% confidence interval = 1.96
Using the relation :
(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)
(10.53-10.55) ± 1.96*sqrt(0.14^2/30 + 0.17^2/25)
Lower boundary :
-0.02 - 0.0833710 = −0.103371
Upper boundary :
-0.02 + 0.0833710 = 0.063371
(−0.103371 ; 0.063371)
B.)
We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.
C.)
For sample size :
n1 = 300 ; n2 = 250
(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)
Lower boundary :
-0.02 - 0.0263642 = −0.0463642
Upper boundary :
-0.02 + 0.0263642 = 0.0063642
( -0.0463642, 0.0063642)
Since 90 degree is 1/4 of a circle, the area will be 1/4 th area of the full circle.
The radius is given by, r = 8 ft, therefore, the area of the full circle is,
Therefore, the area of the sector is,
The volume of this prism is: 240 cm3.
Because, in order to find the volume you have to do: V = w h l = 4 x 15 x 4 = 240.
(V = volume, w = width, h = height, and l = length)
Hope I helped!
- Amber
Answer:
n=36
Step-by-step explanation:
I dont know if thats how it was set up but here you go. I hope this helps. (I can change it if thats not how its set up)
Answer:
i have the answer for the first one, it is 2.55. hope this helps!!
Step-by-step explanation:
