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2 years ago

10

Simplify it

29%29%288r%20-%202p%29" id="TexFormula1" title=" \frac{(6r+9p)(6r-9p)}{3} +( 7p+2(r - 3p))(8r - 2p)" alt=" \frac{(6r+9p)(6r-9p)}{3} +( 7p+2(r - 3p))(8r - 2p)" align="absmiddle" class="latex-formula">
thanks.

1 answer:

dimaraw [331]2 years ago

3 0

Answer:

28r^2 - 29p^2 + 4rp

Step-by-step explanation:

(2r+3p)(6r-9p)+(p+2r)(8r-2p) = 12r^2-18rp+18rp-27p^2+8rp-2p^2+16r^2-4rp =

28r^2 - 29p^2 + 4rp

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Question 10 of 21

PSYCHO15rus [73]

<u>ANSWER</u>

A. (4,12)

<u>EXPLANATION</u>

The equations are:

$10x +2y = 64...(1)$

and

$3x - 4y = -36...(2)$

To eliminate a variable we make the coefficients of that variable the same in both equations.

It is easier to eliminate x.

We multiply the first equation by 2 to get:

$20x + 4y = 128...(3)$

We add equations (2) and (3).

$3x + 20x + 4y - 4y = - 36 + 128$

$23x = 92$

Divide both sides by 23

$\frac{23x}{23} = \frac{92}{23}$

$x = 4$

Put x=4 into equation (1).

$10(4)+2y = 64$

$40+2y = 64$

$2y = 64 - 40$

$2y = 24$

$\frac{2y}{2} = \frac{24}{2}$

$y = 12$

The solution is (4,12)

6 0

3 years ago

Consider the following set of vectors. v1 = 0 0 0 1 , v2 = 0 0 3 1 , v3 = 0 4 3 1 , v4 = 8 4 3 1 Let v1, v2, v3, and v4 be (colu

Alona [7]

Answer:

We have the equation

$c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]$

Then, the augmented matrix of the system is

$\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]$

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

$\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]$

This matrix is in echelon form. Then, now we apply backward substitution:

1.

$8c_4=0\\c_4=0$

2.

$4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0$

3.

$3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0$

4.

$c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0$

Then the system has unique solution that is $(c_1,c_2c_3,c_4)=(0,0,0,0)$ and this imply that the vectors $v_1,v_2,v_3,v_4$ are linear independent.

4 0

2 years ago

Which of the following expressions are equivalent to x + y-z

gavmur [86]

Answer:

C since y-x are being subtracted and there should be another subtraction but there isnt

5 0

2 years ago

Rajah / Diagram 5 (b) Dalam Rajah 6, PQ ialah tangen sepunya dua bulatan. AQ dan BQ ialah tangen bagi bulatan yang masing-masing

Dovator [93]

Answer:

36281629273781646181993836619946527189119292937467482919198$7473828191927364732818919283838292927383883829118661552621718919191019284746617171819001187373765252728

Step-by-step explanation:

173899918377+28910873638282

6 0

2 years ago

Given a 30-60-90 triangle with a long<br> leg of 9 in, determine the length of the<br> hypotenuse.

aniked [119]

Answer:

10.38 in

Step-by-step explanation:

Long side would be opposite to 60°.

Since, side opposite to 60° is root 3 upon 2 times of hypotenuse.

$9 = \frac{ \sqrt{3} }{2} \times hypotenuse \\ \\ hypotenuse = \frac{9 \times 2}{ \sqrt{3} } \\ = \frac{18}{ \sqrt{3} } = \frac{18 \sqrt{3} }{3} = 6 \sqrt{3} = 6 \times 1.73 \\ \: \: \: \red{ \bold{hypotenuse = 10.38 \: in}}$

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2 years ago