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aliya0001 [1]
3 years ago
12

What number is 2,456 to the zero power?

Mathematics
1 answer:
Jlenok [28]3 years ago
3 0
1
This is the correct answer
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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste
olga_2 [115]
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)=(x-a)^{3}

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions: 
 
f(x)=b(x-a)^{3}

4. Now, f(0)=-5 so  -5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}

-5=-ba ^{3}

5=ba ^{3}

b= \frac{5}{ a^{3} }

5. the function is f(x)=\frac{5}{ a^{3} }(x-a)^{3} where a can be any real number except 0
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3 years ago
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I need somebody help on this test i am Taking
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Answer:

ok and thank you for point

3 0
3 years ago
WILL MARK AS BRAINLIEST FOR THESE QUESTIONS.
laiz [17]

1.

Let the sandwich be represented by = x

Let the drink be represented by = y

As given, Joe charges $10.00 for two sandwiches and one drink, so equation becomes 2x+y=10    ....(i)

He charges $6.50 for one sandwich and one drink, so equation becomes x+y=6.50  ....(ii)

Subtracting (ii) from (i) we get

x=3.50

And as x+y=6.50

y=6.50-3.50=3.00

Hence, cost of a sandwich is $3.50 and a drink is $3.00

2.

the question is incomplete. coordinates are missing

3.

Let x represent the number of performances

cost = 8000+300x

revenue = 700x

To break even, the cost must be equal to the revenue.

8000+300x=700x

400x=8000

so x=20

Hence, 20 performances are needed to break even.

4.

Let us take x for 20% material, y for 50% material

\frac{20x+50y}{200}=30

20x+50y=6000    ......... (1)

Accounting for volumes to use, x+y=200 or x=200-y ................ (2)

Putting the value of x in (1)

20(200-y)+50y=6000

4000-20y+50y=6000

4000+30y=6000

30y=2000

y=66.67

x=200-y = 200-66.67 =133.33

Hence, 133.33 ml of 20% acetic acid and 66.67% of 50% acetic acid is needed.





3 0
3 years ago
John has a map that shows a rectangular park with a circular pond. The scale on the map is 114 cm : 8 yd. On the map, the width
Ivenika [448]

Answer:

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm.

Step-by-step explanation:

first we would use A=length x width

so a = 614 cm x 212 cm = 130,168 cm

now we find the area of the pond using a= pi x r^2

the diameter is 114 cm so we cut that in half to find the radius which is 57 cm

a = pi x 57^2

a= 3.14 x 3249

a= 10201.86 cm

now we subtract the area of the pond from the whole area

130,168 - 10201.86 = 119,966.14 cm

The area of the park is 119,966.14 cm if needed to round it would be 119,966 cm

4 0
2 years ago
Simply each expression by combining like terms 2n -5 + 3p -5n + 10p
Shtirlitz [24]
7n +13p + -5 = 15 Hope I helped
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