The number of electrons in outer ring for cesium would be ONE 1.
PKa = -log (Ka) = log [HPO4(2-)] - log[H+]^2 = - log(4.2×10^-13)
pH = - log [H+]
- log [H+]^2 = - 2 log [H+]
2pH = - log (4.2×10^-13) - log [HPO4(2-)]
2pH = - log (4.2×10^-13) - log (0.550)
pH = 6.32
Oak tree, because it’s the primary producer
It is ionic bond because of Na valency and it is alkali metal and cl is non metal and it’s valency , they both share electron and make ionic bonding .
