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mixas84 [53]
3 years ago
6

PLS HELPPP why is CH3OH more polar than CH3CH2OH

Chemistry
1 answer:
dusya [7]3 years ago
8 0

Answer:

Explanation:

Polarity is about differencens in electronegativity. CH bonds have around the same electronegativity value so a CH bond is nonpolar. The more CH bonds there are in a molecule, the more nonpolar it is. Since CH3CH2OH has more carbon-hydrogen bonds than CH3OH, it is more nonpolar. With the same reasoning, since CH3OH has less CH bonds, it's more polar.

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Which of the following pure compounds will exhibit hydrogen bonding?
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Explanation:

For a compound to show hydrogen bonding it is necessary that the hydrogen atom of the compound should be attached to more electronegative atom like fluorine, oxygen or nitrogen.

For example, CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} all these compounds contain an electronegative atom attached to hydrogen atom.

Therefore, these pure compounds will exhibit hydrogen bonding.

Thus, we can conclude that out of the given options CH_{3}CH_{2}OH, CH_{3}NH_{2} and NH_{3} are the pure compounds which will exhibit hydrogen bonding.

4 0
4 years ago
Question 2 The metal molybdenum becomes superconducting at temperatures below 0.90K. Calculate the temperature at which molybden
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Answer:

Temperature at which molybdenum becomes superconducting is-272.25°C

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As given, molybdenum becomes superconducting at temperatures below 0.90 K.

Temperature in Kelvins can be converted in °C by relation:

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Molybdenum becomes superconducting in degrees Celsius.

T(°C)=273.15-0.90= -272.25 °C

Temperature at which molybdenum becomes superconducting is -272.25 °C

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