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ahrayia [7]
3 years ago
12

Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other h

as carbon tetrachloride as the solvent. Determine that concentration and boiling point.
Chemistry
2 answers:
natima [27]3 years ago
5 0
The Boiling point of the benzene would be

bp= 80.1C
 kb=2.53

The boiling point of the carbon tetrachrloride would be
bp=80.1
 kb=50.3 
salantis [7]3 years ago
5 0

Answer:

The concentration should be 1.32 M and the boiling point 83.44 °C

Explanation:

We have two solutions with the same concentration and the same boiling point.

The first solution is benzene as the solvent and the other has carbon tetrachloride as the solvent.

Useful data on the problem:

Boiling point Benzene pure is 80.1 °C and Kbb = 2.53

Boling point carbon tetrachloride pure 76.8 °C and Kbc = 5.03.

The boiling point of the first solution should be:

B1 = 80.1 + 2.53*X1. Where X1 is the concentration in M (mol/L)

The boiling point of the second solution is:

B2 = 76.8 + 5.03*X2. Where X2 is the concentration in M (mol/L).

Both solutions have the same concentration and the same boiling point. We can use the equalities X1 = X2 = X. B1 = B2

B1 = B2

80.1 + 2.53*X = 76.8 + 5.03*X

We can isolate X.

80.1 - 76.8 = (5.03 - 2.53)X

3.3 = 2.5 X

2.5 X = 3.3

X = 3.3/2.5

X = 1.32 M

The concentration of both solutions X1 = X2 = 1.23 M and the boiling point is

80.1 + 2.53(1.32) = 83.44 °C.

Finally, we can conclude that the concentration should be 1.32 M and the boiling point 83.44 °C.

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Mengapa dinding kapilari darah berbeza berbanding dinding vena dan arteri​
olga55 [171]

Answer:

Kapilari lebih kecil dan paling banyak saluran darah, mereka membentuk sambungan antara vesel yang membawa darah dari pendengaran (arteri) dan vesel yang mengembalikan darah ke jantung (urat)

Fungsi utama kapilari ialah pertukaran bahan antara sel darah dan tisu.

Veins membawa darah ke arah jantung; selepas ia melewati kapilari dan masuk melalui urat terkecil (venules).

Arteri membawa darah dari jantung; arteri sistemik mengangkut darah oksigen dari ventrikel kiri ke tisu badan.

Explanation:

(translated version)

Why blood capillary walls differ from veins and arteries

Capillaries are smaller and the most numerous of the blood vessels, they form the connection between the vessels that carry blood away from the hear (arteries) and the vessels that return the blood to the heart (veins)

The primary function of the capillaries is the exchange of materials between the blood and tissue cells.

Veins carries the blood towards the heart; after it passes through the capillaries and enters through the smallest veins (venules).

Arteries carries blood away from the heart; systemic arteries transport oxygenated blood from the left ventricle to the body tissues.

5 0
3 years ago
To what Kelvin temperature must a balloon
snow_tiger [21]

Answer:

T_2=261.46\ K

Explanation:

It is given that,

Original temperature, T_1=323^{\circ}C=596.15\ K

Original volume, V_1=2.85\ L

We need to find the temperature if the volume of the balloon to be shrink to 1.25 L.

According to Charles law, at constant pressure, V\propto T

It would means, \dfrac{V_1}{V_2}=\dfrac{T_1}{T_2}

T₂ = ?

T_2=\dfrac{V_2T_1}{V_1}\\\\T_2=\dfrac{1.25\times 596.15}{2.85}\\\\T_2=261.46\ K

So, the new temperature is 261.46 K.

4 0
3 years ago
If 2 acid have ph value 3 and 5 respectively, which will be more acidic? Why?​
nataly862011 [7]

Answer:

A lower ph is always more acidic, due to the increased concentration of hydrogen ions in the solution/substance.

A ph of 3 is 100 times more acidic than a pH of 5, and this is due to the increments on the scale.

6 0
3 years ago
How many moles of O2 are produced when 0.500mol of KO2 reacts in this fashion?
Shtirlitz [24]
I think you means the KO2 reacts with H2O. The equation of this reaction is 4KO2+2H2O->4KOH +3O2. The ratio of mole number of O2 and KO2 is 3:4. So the mole number of O2 produced is 0.500/4*3=0.375 mol.
6 0
3 years ago
Consider the reversible reaction, A+B⇌C+D. If the concentration of product D is increased, the rate of the reverse reaction woul
natali 33 [55]

Answer:

If the concentration of product D is increased, the rate of the reverse reaction would increase.

Explanation:

Chemical reaction:

A + B ⇄ C + D

In given condition the equilibrium is disturb by increasing the concentration of product.

When the concentration of product D is increased the system will proceed in backward direction in order to regain the equilibrium. Because when the product concentration is high it means reaction is not on equilibrium state the reaction will proceed backward direction to regain the equilibrium state.

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

4 0
3 years ago
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