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3 years ago

ASAP PLEASE HELP also can yall help with describing 4 for me thanks

Mathematics

1 answer:

Stels [109]3 years ago

3 0

4 is a number That u use to count with or something g sorry gotta be more spiscific

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A theater seats 1,000 people. When Jeremy arrives there are 673 empty seats Jeremy is followed by a group of 145 people.how many

kozerog [31]

There will be 181 seat left once Jeremy and the group seat down

7 0

3 years ago

Read 2 more answers

I need help please it’s due tomorrow.......

Sholpan [36]

Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft

see the attached figure
the solution is the shaded area

4 0

3 years ago

determine if the ordered pair is a solution of the equation is (2 4) a solution of y = -3× - 2? true or false

vesna_86 [32]

Answer:

False

Step-by-step explanation:

y = -3× - 2

4 = -3(2) - 2

4 = -6 - 2

4 = -8

4 0

3 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago

For a certain online store, the distribution of number per hour is approximately normal with mean 1200 purchases and standard de

Advocard [28]

Answer: 16%

Step-by-step explanation:

When we have a normal distribution, the 100% of our sample will be placed in a "gaussian bell".

Where the middle of this bell coincides with the mean.

The mean, in this case, is 1200, and the standard deviation is 200.

In the image below you can see that between the points.

Mean + standard deviation and the end of the graph, we have:

13.5% + 2.35% + 0.15% = 16%

And particularly, if we want to know the percentage that exceed 1400, will be the same percentage above the mean plus the standard deviation.

mean = 1200

SD = 200

mean + standard deviation = 1200 + 200 = 1400.

Then the percentage that exceeds 1400 is equal to the percentage that we found above, then the correct option is C: 16%

5 0

3 years ago