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Margarita [4]
3 years ago
9

Find the interest on $4,000 at 3% for 4 months.

Mathematics
1 answer:
tankabanditka [31]3 years ago
5 0

Answer:

$80 interest will be owed for 4 months

Step-by-step explanation:

P is the principal amount, $4000.00.

r is the interest rate, 8% per year, or in decimal form, 8/100=0.08.

t is the time involved, 3....month(s) time periods.

Since your interest rate is "per year" and you gave your time interval in "month(s)" we need to convert your time interval into "year" as well.

Do this by dividing your time, 3- month(s), by 12, since there's 12 months in 1 year.

So, t is 0.25....year time periods.

To find the simple interest, we multiply 4000 × 0.08 × 0.25 to get that:

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etta bought a calculator for $15. Glenn found the same model for $9.79. How much more did Etta pay than Glenn
ololo11 [35]

5.21.

To find this, give both numbers decimal points before setting up a subtraction equation as so:

15.00 - 9.79

Then proceed to solve to get the final answer of 5.21.

Hope this helps!

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4 years ago
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How many groups of 2.4 will divide into 29.52 ?
Bas_tet [7]
29.52/2.4 =12.3
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3 years ago
Write the equation of the line that passes through (5.-9) and (2.5).
Kipish [7]

Answer:

y = -14/3x + 43/3

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - (-9) / 2 - 5

14 / -3

- 14/3

y = -14/3x + b

5 = -14/3(2) + b

5 = -28/3 + b

43/3 = b

y = -14/3x + 43/3

4 0
3 years ago
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

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