Answer:
The height of the painting is 28.7525 in and the width is 23.7425 in
Step-by-step explanation:
Let
x -----> the height of the painting
y -----> the width of the painting
we know that
The perimeter of the painting is
so
----> equation A
----> equation B
substitute equation B in equation A and solve for y
Find the value of x
therefore
The height of the painting is 28.7525 in and the width is 23.7425 in
Answer:
(a).4.36 mph
(b) No
Step-by-step explanation:
We are given that
Jan covered distance,s1 =2 miles
Speed of Jan, a=3 mph
s2=1 mile
b=8mph
a.
We have to find the Jan' s average speed for the entire trip.
Average speed =
Using the formula
Average speed=
b.
Average speed with two speed
Average of Jan’s two speeds
=
Hence, the average speed in part (a) is not equal to the average of Jan’s two speeds.
So, The Circumference of a triangle is located in the center of a triangle. hope this helps :)
V = x · y²
2 x + y = 3
y = 3 - 2 x
V = x · ( 3 - 2 x )² = x · ( 9 - 12 x + 4 x² ) = 9 x - 12 x² + 4 x³
V ` = 9 - 24 x + 12 x² = 3 ( 4 x² - 8 x + 3 ) = 3 ( 4 x² - 6 x - 2 x + 3 ) =
= 3 [ 2 x ( 2 x - 3 ) - ( 2 x - 3 ) ] = 3 ( 2 x - 3 ) ( 2 x - 1 )
The largest volume is when: V ` = 0, so:
2 x - 3 = 0
2 x = 3
x = 1.5 ( which is incorrect, because : y = 0 )
or: 2 x - 1 = 0
2 x = 1
x = 0.5, y = 3 - 2 · 0.5 = 3 - 1 = 2
V max = 0.5 · 2² = 0.5 · 4 = 2 ft³
1 1/3 - 2/3 =
4/3 - 2/3 =
2/3 <==
