The base is 4 x 10. which means that you can divide 160 by 40 to get the hieght. (The height is 4)
That would be Graph C
The solution is where the 2 graphs intersect At A and B.
x + y + 2 = 0 transforms to y = -x - 2 which has slope -1 and y-intercept of -2
as in Graph C.
You would add up all of the numbers and then divide them by 5 since you have a total of 5 different sets of numbers (To get the mean). Then you have to find the median by putting all of the numbers in numerical order and get the number in the middle. Finally you subtract the median from the mean and you end up getting “B” as your answer.
Let G be some point on the diagonal line away from point E.
Angle DEG represents angle 1.
We're given that angle DEF is a right angle which means it's 90 degrees. Angle DEG is some angle smaller than 90 degrees. By definition, that must mean angle 1 is acute. Any acute angle is smaller than 90 degrees. There's not much else to say other than this is just a definition problem.
----------------
Extra side notes:
If angle 1 was a right angle, then that would mean angle GEF would have to be 0 degrees; however the diagram shows this isn't the case.
If angle 1 was obtuse, then there's no way we'd be able to fit it into angle DEF. In other words, there's no way to have an angle larger than 90 fit in a 90 degree angle.
It equals 99. 4 times 9 equals 36. 11 times 9 equals 99.