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Flura [38]
3 years ago
10

-8 (c - 10) = - (c-3)

Mathematics
2 answers:
makkiz [27]3 years ago
7 0
Hope this helps and pls tell me if you like my handwriting

Gre4nikov [31]3 years ago
3 0

1 Remove parentheses.

-8(c-10)=−c+3

2 Regroup terms.

-8(c-10)=3−c

3 Expand.

-8c+80=3−c

4 Add 8c8c to both sides.

80=3−c+8c

5 Simplify 3-c+8c to 3+7c

80=33+7c

6 Subtract 33 from both sides.

80-3=7c

7 Simplify 80-3 to 77.

77=7c

8 Divide both sides by 7.

77/7 = c

9 Simplify 77/7 to 11.

11=c

10 Switch sides.

c=11

Sorry about my comment its all messed up, I thought you added a fraction like you did in an answer. Someone answered before me and i just copied mine and pasted it into a comment but it made it all weird. Happy holidays

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Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

a^2 cancels out a^5 remaining a^3 denominator

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c3 cancels out c8 = c5 remaining denominator

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4 0
3 years ago
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Sergio039 [100]

Answer:

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Apologies if I am incorrect.

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4 years ago
Ravi drove 693 miles in 11 hours.
gregori [183]

Answer:

Step-by-step explanation:

Set up a proportion

693 miles / 11 hours = 315 miles / x hours

Notice that the numerators both have the same units (miles).

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693x = 3465                                Divide by 693

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4 0
3 years ago
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Step-by-step explanation:

26/7 ×35/ 8 =910/56

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3 years ago
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AVprozaik [17]

Given:

Coordinates of point A are (7,3).

Point B is on the x-axis whose abscissa is 11.

To find:

The distance between A and B.

Solution:

Point B is on the x-axis whose abscissa is 11. So, x-coordinate of the point B is 11 and y-coordinate is 0. It means, coordinates of point B are (11,0).

The distance between A(7,3) and B(11,0) is

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

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