Since

The square root of 11 is somewhere between 3 and 4. In order to round it to the nearest tenth, we have to try all numbers between 3 and 4 with one decimal digit, and see which is closest to 11 when squared. We have
![\begin{array}{c|c}n&n^2\\3&9\\3.1&9.61\\3.2&10.24\\3.3&10.89\\3.4&11.56\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7Cc%7Dn%26n%5E2%5C%5C3%269%5C%5C3.1%269.61%5C%5C3.2%2610.24%5C%5C3.3%2610.89%5C%5C3.4%2611.56%5Cend%7Barray%7D%5Cright%5D)
So, the square root of 11 is somewhere between 3.3 and 3.4.
Answer:
78
Step-by-step explanation:
4(x) = 4(7) = 28 5(x) = 5(10) = 50
28+50=
78
You could 3•2 because your it two times =6 than it’s 2\6 make more smaller 1/3 it will be. Than you get .3333 repeating
Answer:
A=110.88
Step-by-step explanation:
Use the formula of a triangle- a=bxh/2
Then multiply by 4 since there are four equilateral triangles in the net
Answer:
2:1
Step-by-step explanation:
well we show ratio by the sign ' : '
ratio of iced tea to lemonade= 12:6
now we reduce it to minimum by dividing it with same number.
12 is divisible by 6
so,
the reduced form is = 2:1
therefore,
ratio of the number of students who want iced tea to the number of students who want lemonade = 2:1.