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3 years ago

Pls help its past due 11 days

Mathematics

1 answer:

oee [108]3 years ago

4 0

Answer:

17 sorry

Step-by-step explanation:

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How do i solve (3c^2d^4) ^3 x (2c^5d^8)^3?

vredina [299]

Answer:

$216c^{21}d^{36}$

Step-by-step explanation:

$(3c^2d^4)^3 * (2x^5d^8)^3$

$(3c^2)^3 (d^4)^3 * (2c^5)^3 (d^8)^3$

$27c^6 d^{12} * 8c^{15} d^{24}$

$216c^{21}d^{36}$

Hope this helps!

7 0

2 years ago

What is the vertical asymptote of the rational function f(x) = 3x / (2x - 1)?

sp2606 [1]

Answer:

1/2 is your vertical asymptote

4 0

3 years ago

MUST BE CORRECT ANSWER HELP ASAP

Nina [5.8K]

Answer:

40287600 = B. 4 x $10^{7}$

Step-by-step explanation:

We first have to do the multiplication of the numbers given:

19 * 2,120,400

=> 40287600

Now we have to figure out how many digits are after the number 4:

4, 0 2 8 7 6 0 0

7 digits

Meaning that we need an exponent of 7 for it to be in scientific notation, giving us with the answer B. 4 x $10^{7}$

6 0

3 years ago

Solve for x A) 36 B) 54 C) 72 D) 84 Ayo help a girl out

kykrilka [37]

Answer:

72°

Step-by-step explanation:

This is called an isosceles triangle. This means that the 2 angles related to the equal sides, are also equal. Hence, the answer is 72°

6 0

3 years ago

Read 2 more answers

If 4 Maths books are selected from 6 different Maths different English books, how many ways can the seven om Maths books and 3 E

alexgriva [62]

Answer:

Please see the answer below

Step-by-step explanation:

a. Since there’s no restrictions .Therefore , the number of ways = 7!*150 = 756000

b. The number of ways such that the 4 math books remain together

The pattern is as follows: MMMMEEE, EMMMMEE, EEMMMME, and EEEMMMM

Where M = Math’s Book and E= English Book.

Number of ways = 4!*8!*4*150= 86400 ways.

c. The number of ways such that math book is at the beginning of the shelf

The number of ways = 6!*4*150 = 432000

d. The number of ways such that math and English books alternate

The number of ways = 150*4!*3! =2160 ways

e. The number of ways such that math is at the beginning and an English book is in the middle of the shelf. The number of ways = 4*3*5!*150 =216000 ways.

6 0

3 years ago