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Nuetrik [128]
3 years ago
12

The radius of a softball is almost 2 inches. The radius of a basketball is almost 5 inches How would the volume of a basketball

compare to the volume of a softball ?
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0
I think that the basketball's volume would be greater than the softball because it has a radius of 5 and the softball has a radius of 2. 
jek_recluse [69]3 years ago
7 0

Answer:

It would 15.6251865115 times the volume of the soft ball. Rounded would be 15.625 times the volume.

Step-by-step explanation:

Use the formula 4/3πr cubed. 2 cubes is 8. 8pi is 25.1327412287. 25.1327412287*4/3 is 33.5103216383 rounded would be 33.5. Do the same thing for the radius as 5 and you would get 523.6. i divided 523.6 by 33.5 and you would get around 15.625.

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An electronics store buys a television at a wholesale price of $120. The store then sells the television to its customers for $3
algol [13]
180% from the selling price to the wholesale
7 0
3 years ago
Please answer both questions and show all work with explanations :) thank you soo much...
torisob [31]

Answer:

1) 109 cm

2) 120 in²

Step-by-step explanation:

A rectangle is a quadrilateral with opposite sides the same length and four (4) right angles. The diagonal, together with two adjacent sides, forms a right triangle. The relationship between side lengths and the diagonal length is given by the Pythagorean theorem. If sides are "a" and "b" and the diagonal is "c", that theorem tells you ...

... c² = a² + b²

1) c² = (60 cm)² + (91 cm)² = 11881 cm²

... c = √11881 cm = 109 cm

2) The perimeter is double the sum of adjacent side lengths, so ...

... 2(a+b) = 46 in

... a + b = 23 in . . . . . divide by 2

The Pythagorean theorem tells you

... a² + b² = (17 in)²

Squaring the equation from the perimeter relation gives ...

... (a + b)² = (23 in)² = a² + 2ab + b²

Subtracting a² + b², we have

... (a² +2ab +b²) - (a² + b²) = (23 in)² -(17 in)²

... 2ab = (529 -289) in² = 240 in² . . . . . simplify

... 240 in²/2 = ab = 120 in² . . . . . area is the product of length and width

_____

We could solve the two equations for a and b to find that there are two possible solutions: (a, b) = (8, 15) or (15, 8). Either way, ab = 8·15 = 120.

7 0
3 years ago
What are the truck ID’s of trucks that have carried small shipments. Small shipments are defined as those that weigh less than 8
Ivanshal [37]

Table for the question is attached in the picture below :

Answer:

SELECT distinct(TRUCK_ID), WEIGHT from SHIPMENT where WEIGHT < 800 ;

Step-by-step explanation:

The Structured query language (SQL) defined above, returns only the TRUCK_ID and Weight column from the shipment table as they are the only two columns listed after the select keyword. The condition is added using the WHERE keyword on the weight table, this filters the result returned to include only rows where the weight value is less than 800. The distinct keyword used alongside the TRUCK_ID column ensures that a certian TRUCK_ID value isn't returned more than once (Hence, it is used to avoid duplicates).

5 0
3 years ago
What is the volume of a cylinder in a cubic cm,with a height of 8cm and a base diameter of 16 cm?round to the nearest tenth plac
Allushta [10]

Answer:

V≈1608.5

Step-by-step explanation:

3 0
2 years ago
Look at the bottom the little question HELPPPPPP
likoan [24]

Answer:

10

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(f + g)(2) = f (2) + g(2)

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              = -8 + 18 = 10

8 0
3 years ago
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