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Nuetrik [128]
3 years ago
12

The radius of a softball is almost 2 inches. The radius of a basketball is almost 5 inches How would the volume of a basketball

compare to the volume of a softball ?
Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
7 0
I think that the basketball's volume would be greater than the softball because it has a radius of 5 and the softball has a radius of 2. 
jek_recluse [69]3 years ago
7 0

Answer:

It would 15.6251865115 times the volume of the soft ball. Rounded would be 15.625 times the volume.

Step-by-step explanation:

Use the formula 4/3πr cubed. 2 cubes is 8. 8pi is 25.1327412287. 25.1327412287*4/3 is 33.5103216383 rounded would be 33.5. Do the same thing for the radius as 5 and you would get 523.6. i divided 523.6 by 33.5 and you would get around 15.625.

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A moving company charges 40$ plus 0.25$ per mile to rent a van. Another company charges 25$ plus o.35$ per mile to rent the same
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3 years ago
5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
Plzzz helpp find the length of arc AD. use 3.14 for pi. round to the nearest tenth
solniwko [45]

Answer:

15.7 cm

Step-by-step explanation:

Angle AD = 180°- 66.4°= 113.6° (considering 2x90°=180° on opposite side)

P= 2*3.14*7.9=49.6 cm

Arc AD= 49.6*113.6°/360°= 15.7 cm

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3 years ago
6 inches for every horizontal change of 12 inches
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Skjsjskskskkskskskksskksksksksksks
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4 years ago
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