Answer:
2/6
3/9
4/12
Step-by-step explanation:
-5 1/8 would round to -5
-9 3/4 would round to -10
1 37/41 would round to 2
-5(2)=-10
Hope this helped :)
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
From the Arithmetic Information given, Pr = 0.049375 ≠ -8.050625 ≠ 0.0325 See explanation below.
<h3>
What are the step by steps solution to the questions above?</h3>
First, lets us restate the question properly. We have
Pr = 1 - ((6*12+6)/80)² = 1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) = 1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
Note that there are three equals signs. So lets divide the problem according and solve for the different parts.
Lets 1 - ((6*12+6)/80)² ............A
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400) .............B; and
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6² ........C
Solving for A we have
1 - (78/80)²
= 1 - (0.975)²
= 1 - 0.950625
A = 0.049375
Solving for B we have
1 - ((9*12²)/1600) - ((3*12*6)/1600) - (6²/6400)
= 1- (14,256/1600) - (216/1600) - (36/6400)
= 1 - 8.91 - 0.135 - 0.005625
B = -8.050625
Solving for C we have
1 - 0.005625 * 12² - 0.001875 * 12 * 6 - 0.00015625 * 6²
= 1 - 0.005625 * 144 - 0.001875 * 12 * 6 - 0.00015625 * 144
= 0.0325
In summary we can state that:
A = 0.049375
B = -8.050625
C = 0.0325
Given that there were no abstract quantities, we can state that
Pr = A ≠ B ≠C or
Pr = 0.049375 ≠ -8.050625 ≠ 0.0325
Learn more about equations with equal signs at
brainly.com/question/18924248
#SPJ1
→ Solutions
⇒ Simplify <span><span><span>4<span>(<span>2a</span>)</span></span>+<span>7<span>(<span>−<span>4b</span></span>)</span></span></span>+<span><span>3c</span><span>(5)</span></span></span><span>⇒ </span><span><span><span><span><span>8a</span>+</span>−<span>28b</span></span>+<span>15<span>c
Answer
</span></span></span></span><span>⇒ </span><span>8a−28b</span><span>+</span><span>15c</span>
