Answer:
3/4
Step-by-step explanation:
A: students present
B: students on time
P(all students present and on time) = P(A and B) = 3/10
P(all students present) = P(A) = 2/5
P(A and B) = P(A).P(B|A) where P(B|A) is the probability of everyone being on time given that everyone is present
So P(B|A) = P(A and B) /P(A) = 3/10 ÷ 2/5 = 3/10 * 5/2 = 15/20 which can be reduced to 3/4 by dividing numerator and denominator by 5
The answer would be D. 18/6. We can figure this out because in the question, it says that each shape is worth one whole. There are three shapes so that means when added, the sum is 3 and 18/6, when reduced is 3.
I hope this helped! :-)
Answer:
I hope this answer helps you
C. 2 games that cost a total of $10.00