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pochemuha
3 years ago
12

If (x,y) is a solution to the system of equations shown below, what is the product of the y-coordinates of the solutions? x^2+4y

^2=40 x+2y=8

Mathematics
1 answer:
aliina [53]3 years ago
4 0

Answer:

The product of the y-coordinates of the solutions is equal to 3

Step-by-step explanation:

we have

x^{2}+4y^{2}=40 -----> equation A

x+2y=8 ------> equation B

Solve by graphing

Remember that the solutions of the system of equations are the intersection point both graphs

using a graphing tool

The solutions are the points (2,3) and (6,1)

see the attached figure

The y-coordinates of the solutions are 3 and 1

therefore

The product of the y-coordinates of the solutions is equal to

(3)(1)=3

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Answer:

x = \displaystyle \frac{5 + \sqrt{17}}{2}.

Step-by-step explanation:

Because 3\, x is found in the input to a logarithm function in the original equation, it must be true that 3\, x > 0. Therefore, x > 0.

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Left-hand side of this equation:

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Right-hand side of this equation:

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The natural logarithm function \ln is one-to-one for all positive inputs. Therefore, for the equality \begin{aligned}\ln\left(\frac{3\, x}{x -4}\right) = \ln(3(2\, x - 1))\end{aligned} to hold, the two inputs to the logarithm function have to be equal and positive. That is:

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