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AURORKA [14]
3 years ago
6

circle centered at the origin has a radius of 5 units. The terminal side of an angle, θ, intercepts the circle in Quadrant IV at

point C. The x-coordinate of point C is 3. What is the value of sin θ?
Mathematics
1 answer:
astraxan [27]3 years ago
5 0

Answer:

Step-by-step explanation:

x²+y² = 5²

3²+y² = 25

y² = 16

y = ±√16 = ±4

Since the terminal side is  in quadrant IV, y = -4

sinθ = -4/5

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Discrete Math
andrezito [222]

Answer:

Part c: Contained within the explanation

Part b: gcd(1200,560)=80

Part a: q=-6         r=1

Step-by-step explanation:

I will start with c and work my way up:

Part c:

Proof:

We want to shoe that bL=a+c for some integer L given:

bM=a for some integer M and bK=c for some integer K.

If a=bM and c=bK,

then a+c=bM+bK.

a+c=bM+bK

a+c=b(M+K) by factoring using distributive property

Now we have what we wanted to prove since integers are closed under addition.  M+K is an integer since M and K are integers.

So L=M+K in bL=a+c.

We have shown b|(a+c) given b|a and b|c.

//

Part b:

We are going to use Euclidean's Algorithm.

Start with bigger number and see how much smaller number goes into it:

1200=2(560)+80

560=80(7)

This implies the remainder before the remainder is 0 is the greatest common factor of 1200 and 560. So the greatest common factor of 1200 and 560 is 80.

Part a:

Find q and r such that:

-65=q(11)+r

We want to find q and r such that they satisfy the division algorithm.

r is suppose to be a positive integer less than 11.

So q=-6 gives:

-65=(-6)(11)+r

-65=-66+r

So r=1 since r=-65+66.

So q=-6 while r=1.

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Answer:

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243 words per 3 minutes

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81 times 10 = 810

3 0
2 years ago
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A regular pentagon shares a common center with a regular hexagon. If `bar(LM)` || `bar(AB)`, across how many lines of reflection
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our lines of symmetry is made limited by the presence of the pentagon. If we slice the pentagon into two, the only line of symmetry we could create would be the line intersecting O and the median of LM. Other lines would not create a symmetrical half.

Therefore the line of reflection is only 1.

questioned answered by

(jacemorris04)



5 0
3 years ago
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