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pantera1 [17]
3 years ago
15

AB, CD and EF are straight lines. AB is parallel to CD. work out the size of angle y.

Mathematics
1 answer:
Yuri [45]3 years ago
4 0

Answer:

y = 108°

Step-by-step explanation:

Since, line AB is parallel to line CD,

By the definition of corresponding angles,

m∠FPB = m∠FQD

(2x + 16)° = (3x - 12)°

3x - 2x = 16 + 12

x = 28

(3x - 12) = 3(28) - 12

             = 72°

m∠FQD + m∠EQD = 180° [Linear pair of angles]

72° + y = 180°

y = 180 - 72

y = 108°

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Svetradugi [14.3K]
Everything on the sheet looks correct to me. Nice work !
7 0
4 years ago
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A research report from an independent-measures study states that there are significant differences between treatments, F(3, 48)
Flura [38]

Answer:

k = 4 ;

N = 52

Step-by-step explanation:

Given the ratio F(3, 48)

F takes in degree of freedom values; degree of freedom of groups ; degree of freedom of error

Hence,

df group or treatment = 3

df error = 48

df treatment = k - 1

k = Number of groups

3 = k - 1

3 + 1 = k - 1 + 1

4 = k

Number of treatment condition = 4

df error = N-k

N = total number of observations

48 = N - 4

48 + 4 = N - 4 + 4

52 = N

7 0
3 years ago
If f(x)= <br><img src="https://tex.z-dn.net/?f=x%20-%20%7Bx%7D%5E%7B2%7D%20" id="TexFormula1" title="x - {x}^{2} " alt="x - {x}^
astra-53 [7]

Answer:

f(2+h)=-(h+2/3)^2+1/4

f(x+h)=-(x+h-1/2)^2+1/4

Step-by-step explanation:

1. f(2+h)=(2+h)-(2+h)^2=2+h-4-4h-h^2=-h^2-3h-2=-(h^2+3h+2)

=-(h+2/3)^2+1/4

2. Let (x+h)=a, then rewrite the equation into f(a)=a-a^2.

a-a^2=-(a^2-a)=-[(a-1/2)^2-1/4]=-(a-1/2)^2+1/4.

Insert a=x+h, f(x+h)=-(x+h-1/2)^2+1/4

7 0
3 years ago
What are the coordinates of point P on the directed line
lutik1710 [3]

Answer:

<u>(</u><u>-3.5, 2.3</u><u>)</u>

Step-by-step explanation:

Let the point P have coordinates : (x, y)

The line (from R to Q) is divided in the ratio :

Coordinates of :

  • Q = (-5, 3)
  • R = (4, -1)

Using section formula :

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The coordinates of the point P are : <u>(</u><u>-3.5, 2.3</u><u>)</u>

7 0
2 years ago
Marty lives 2/3 mile from school. Linda lives 3/4 as far from school as Marty does. how far does Linda live from school?
Arturiano [62]
A half mile
\frac{2}{3}•\frac{3}{4}=\frac{6}{12}
Which simplifies to \frac{1}{2}
Hope that helps
7 0
3 years ago
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