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3 years ago

Y + 4x = 8 and 5x + 2y = 13

1 answer:

4 0

Y + 4x = 8
y = 8 - 4x
substitute 8 - 4x for y in the other equation.
5x + 2(8 - 4x) = 13
5x + 16 - 8x = 13
-3x = -3
x = 1
y = 8 - 4(1) = 4

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Which shows the following expression after the negative exponents have been eliminated?

SVETLANKA909090 [29]

Answer:

$\frac{a^3b^4}{ab^2}$ which is the last choice in the question

Step-by-step explanation:

Simplify

$\frac{a^3b^{-2}}{ab^{-4}} = \frac{a^3}{a}\frac{b^{-2}}{b^{-4}}$

Using the fact that $\frac{x^m}{x^n} =x^{m-n}$

We get

$\frac{a^3}{a} = a^{3-1} = a^2$

$\frac{b^{-2}}{b^{-4}} = b^{-2-(-4)} = b^2$

$\frac{a^3b^{-2}}{ab^{-4}} =a^2b^2$

Multiplying numerator and denominator by $ab^2$ gives

$a^2b^2 \frac{ab^2}{ab^2}$

= $\frac{a^3b^4}{ab^2}$ ANSWER

Hint:

We can eliminate first choice since negative exponents still remain

We can eliminate third choice because the expression has a minus sign which is not possible

That just leaves second and fourth choices to work with

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1 year ago

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Answer:

the answer is A

Step-by-step explanation:

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3 years ago

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2 years ago

What is V125 in simplest form?

kvv77 [185]

Answer:

5 $\sqrt{5}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$ , then

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago