Answer:
The program to this question can be given as:
Program:
#include <iostream> //header file
using namespace std; //using namespace.
void SwapValues(int* userVal1, int* userVal2); //function declaration.
void SwapValues(int* userVal1, int* userVal2) //function definition.
{ //function body.
//perform swapping
int t = *userVal1;
*userVal1 = *userVal2;
*userVal2 = t;
}
int main() //main method
{
int n1, n2; //define variable
cout<<"Enter first number :"; //message
cin>>n1; //input by user.
cout<<"Enter second number :"; //message
cin>>n2; //input by user.
SwapValues(&n1,&n2); //calling function.
cout<<"Swapped values"<<endl;
cout<<"first number is :"<<n1<<endl; //print value
cout<<"second number is:"<<n2<<endl; //print value
return 0;
}
Output:
Enter first number :3
Enter second number :8
Swapped values
first number is :8
second number is :3
Explanation:
The description of the above C++ language program can be given as:
- In the program, firstly we include the header file. Then we declare and define a function that is "SwapValues()" function in the function we pass two integer variable that is "userVal1 and userVal2" inside a function, we define an integer variable that is "t" and perform swapping.
- Then we define the main function in the main function we define two variables that is "n1 and n2" this variable is used to take value-form user. then we pass this value to function and print the function values.
Answer:
Merge sort is a sorting technique based on divide and conquer technique.
Explanation:
MERGE(A, p, q, r)
n1 = q - p + 1
n2 = r - q
L[1..n1] and R[1..n2] this creates the new array
for i = 1 to n1
L[i] = A[p + i - 1]
for j = 1 to n2
R[j] = A[q + j]
i = 1
j = 1
for k = p to r
if i > n1
A[k] = R[j]
j = j + 1
else if j > n2
A[k] = L[i]
i = i + 1
else if L[i] ≤ R[j]
A[k] = L[i]
i = i + 1
else
A[k] = R[j]
j = j + 1
Answer:
what?
Explanation:
explain a little better please
Answer:
(i) The rotation speed must stay the same.
(ii) The rotation speed must increase.
(iii) The rotation speed must decrease.
Explanation:
According to Equation
10.10, the angular speed must therefore vary as the laser–lens system moves
radially along the disc. In a typical CD player, the constant speed of the surface at
the point of the laser–lens system is 1.3 m/s.